C#中的JSON格式化程序？

Question

寻找一个将stringJson作为输入的函数,并使用换行符和缩进对其进行格式化.验证将是一个奖励,但不是必需的,我不需要将其解析为对象或任何东西.

有人知道这样的图书馆吗？

---

样本输入:

{"status":"OK", "results":[ {"types":[ "locality", "political"], "formatted_address":"New York, NY, USA", "address_components":[ {"long_name":"New York", "short_name":"New York", "types":[ "locality", "political"]}, {"long_name":"New York", "short_name":"New York", "types":[ "administrative_area_level_2", "political"]}, {"long_name":"New York", "short_name":"NY", "types":[ "administrative_area_level_1", "political"]}, {"long_name":"United States", "short_name":"US", "types":[ "country", "political"]}], "geometry":{"location":{"lat":40.7143528, "lng":-74.0059731}, "location_type":"APPROXIMATE", "viewport":{"southwest":{"lat":40.5788964, "lng":-74.2620919}, "northeast":{"lat":40.8495342, "lng":-73.7498543}}, "bounds":{"southwest":{"lat":40.4773990, "lng":-74.2590900}, "northeast":{"lat":40.9175770, "lng":-73.7002720}}}}]} 

Answer 1

我更新了旧版本,现在它应该支持不带引号的值,如整数和布尔值.

我重构了以前的版本并获得了最终版本:代码更短更清晰.只需要一种扩展方法.最重要的是:修复了一些错误.

class JsonHelper
{
    private const string INDENT_STRING = "    ";
    public static string FormatJson(string str)
    {
        var indent = 0;
        var quoted = false;
        var sb = new StringBuilder();
        for (var i = 0; i < str.Length; i++)
        {
            var ch = str[i];
            switch (ch)
            {
                case '{':
                case '[':
                    sb.Append(ch);
                    if (!quoted)
                    {
                        sb.AppendLine();
                        Enumerable.Range(0, ++indent).ForEach(item => sb.Append(INDENT_STRING));
                    }
                    break;
                case '}':
                case ']':
                    if (!quoted)
                    {
                        sb.AppendLine();
                        Enumerable.Range(0, --indent).ForEach(item => sb.Append(INDENT_STRING));
                    }
                    sb.Append(ch);
                    break;
                case '"':
                    sb.Append(ch);
                    bool escaped = false;
                    var index = i;
                    while (index > 0 && str[--index] == '\\')
                        escaped = !escaped;
                    if (!escaped)
                        quoted = !quoted;
                    break;
                case ',':
                    sb.Append(ch);
                    if (!quoted)
                    {
                        sb.AppendLine();
                        Enumerable.Range(0, indent).ForEach(item => sb.Append(INDENT_STRING));
                    }
                    break;
                case ':':
                    sb.Append(ch);
                    if (!quoted)
                        sb.Append(" ");
                    break;
                default:
                    sb.Append(ch);
                    break;
            }
        }
        return sb.ToString();
    }
}

static class Extensions
{
    public static void ForEach<T>(this IEnumerable<T> ie, Action<T> action)
    {
        foreach (var i in ie)
        {
            action(i);
        }
    }
}

Answer 2

您也可以使用Newtonsoft.Json库并使用Formatting.Indented枚举调用SerializeObject -

var x = JsonConvert.SerializeObject(jsonString, Formatting.Indented);

文档:序列化对象

更新 -

刚试了一遍.很确定这曾经发挥作用 - 也许它在后续版本中有所改变,或者我只是想象一下.无论如何,根据下面的评论,它并没有像预期的那样完全奏效.然而,这些(仅在linqpad中测试).第一个来自评论,第二个是我在SO其他地方找到的一个例子 -

void Main()
{
    //Example 1
    var t = "{\"x\":57,\"y\":57.0,\"z\":\"Yes\"}";
    var obj = Newtonsoft.Json.JsonConvert.DeserializeObject(t); 
    var f = Newtonsoft.Json.JsonConvert.SerializeObject(obj, Newtonsoft.Json.Formatting.Indented);
    Console.WriteLine(f);

    //Example 2
    JToken jt = JToken.Parse(t);
    string formatted = jt.ToString(Newtonsoft.Json.Formatting.Indented);
    Console.WriteLine(formatted);

    //Example 2 in one line -
    Console.WriteLine(JToken.Parse(t).ToString(Newtonsoft.Json.Formatting.Indented));
}

Answer 3

json.net库的较短示例.

using Newtonsoft.Json;

private static string format_json(string json)
{
    dynamic parsedJson = JsonConvert.DeserializeObject(json);
    return JsonConvert.SerializeObject(parsedJson, Formatting.Indented);
}

PS:您可以使用标签包装格式化的json文本,以便在html页面上进行打印.

Answer 4

这对我在 .Net Core 3.1 中使用 System.Text.Json 有用

 public string PrettyJson(string unPrettyJson)
 {
     var options = new JsonSerializerOptions(){
         WriteIndented = true
     };

     var jsonElement = JsonSerializer.Deserialize<JsonElement>(unPrettyJson);

     return JsonSerializer.Serialize(jsonElement, options);
 }

Answer 5

这是JSON美化器的紧凑版本.

private const string INDENT_STRING = "    ";

static string FormatJson(string json) {

    int indentation = 0;
    int quoteCount = 0;
    var result = 
        from ch in json
        let quotes = ch == '"' ? quoteCount++ : quoteCount
        let lineBreak = ch == ',' && quotes % 2 == 0 ? ch + Environment.NewLine +  String.Concat(Enumerable.Repeat(INDENT_STRING, indentation)) : null
        let openChar = ch == '{' || ch == '[' ? ch + Environment.NewLine + String.Concat(Enumerable.Repeat(INDENT_STRING, ++indentation)) : ch.ToString()
        let closeChar = ch == '}' || ch == ']' ? Environment.NewLine + String.Concat(Enumerable.Repeat(INDENT_STRING, --indentation)) + ch : ch.ToString()
        select lineBreak == null    
                    ? openChar.Length > 1 
                        ? openChar 
                        : closeChar
                    : lineBreak;

    return String.Concat(result);
}

输出:

 {
    "status":"OK",
     "results":[
         {
            "types":[
                 "locality",
                 "political"
            ],
             "formatted_address":"New York, NY, USA",
             "address_components":[
                 {
                    "long_name":"New York",
                     "short_name":"New York",
                     "types":[
                         "locality",
                         "political"
                    ]
                },
                 {
                    "long_name":"New York",
                     "short_name":"New York",
                     "types":[
                         "administrative_area_level_2",
                         "political"
                    ]
                },
                 {
                    "long_name":"New York",
                     "short_name":"NY",
                     "types":[
                         "administrative_area_level_1",
                         "political"
                    ]
                },
                 {
                    "long_name":"United States",
                     "short_name":"US",
                     "types":[
                         "country",
                         "political"
                    ]
                }
            ],
             "geometry":{
                "location":{
                    "lat":40.7143528,
                     "lng":-74.0059731
                },
                 "location_type":"APPROXIMATE",
                 "viewport":{
                    "southwest":{
                        "lat":40.5788964,
                         "lng":-74.2620919
                    },
                     "northeast":{
                        "lat":40.8495342,
                         "lng":-73.7498543
                    }
                },
                 "bounds":{
                    "southwest":{
                        "lat":40.4773990,
                         "lng":-74.2590900
                    },
                     "northeast":{
                        "lat":40.9175770,
                         "lng":-73.7002720
                    }
                }
            }
        }
    ]
}

Answer 6

我非常深刻的印象紧凑JSON格式由文斯Panuccio。
这是我现在使用的改进版本：

public static string FormatJson(string json, string indent = "  ")
{
    var indentation = 0;
    var quoteCount = 0;
    var escapeCount = 0;

    var result =
        from ch in json ?? string.Empty
        let escaped = (ch == '\\' ? escapeCount++ : escapeCount > 0 ? escapeCount-- : escapeCount) > 0
        let quotes = ch == '"' && !escaped ? quoteCount++ : quoteCount
        let unquoted = quotes % 2 == 0
        let colon = ch == ':' && unquoted ? ": " : null
        let nospace = char.IsWhiteSpace(ch) && unquoted ? string.Empty : null
        let lineBreak = ch == ',' && unquoted ? ch + Environment.NewLine + string.Concat(Enumerable.Repeat(indent, indentation)) : null
        let openChar = (ch == '{' || ch == '[') && unquoted ? ch + Environment.NewLine + string.Concat(Enumerable.Repeat(indent, ++indentation)) : ch.ToString()
        let closeChar = (ch == '}' || ch == ']') && unquoted ? Environment.NewLine + string.Concat(Enumerable.Repeat(indent, --indentation)) + ch : ch.ToString()
        select colon ?? nospace ?? lineBreak ?? (
            openChar.Length > 1 ? openChar : closeChar
        );

    return string.Concat(result);
}

它修复了以下问题：

1. 字符串中的转义序列
2. 冒号后缺少空格
3. 逗号（或其他地方）后的额外空格
4. 字符串内的方括号和花括号
5. 空输入不会失败

输出：

{
  "status": "OK",
  "results": [
    {
      "types": [
        "locality",
        "political"
      ],
      "formatted_address": "New York, NY, USA",
      "address_components": [
        {
          "long_name": "New York",
          "short_name": "New York",
          "types": [
            "locality",
            "political"
          ]
        },
        {
          "long_name": "New York",
          "short_name": "New York",
          "types": [
            "administrative_area_level_2",
            "political"
          ]
        },
        {
          "long_name": "New York",
          "short_name": "NY",
          "types": [
            "administrative_area_level_1",
            "political"
          ]
        },
        {
          "long_name": "United States",
          "short_name": "US",
          "types": [
            "country",
            "political"
          ]
        }
      ],
      "geometry": {
        "location": {
          "lat": 40.7143528,
          "lng": -74.0059731
        },
        "location_type": "APPROXIMATE",
        "viewport": {
          "southwest": {
            "lat": 40.5788964,
            "lng": -74.2620919
          },
          "northeast": {
            "lat": 40.8495342,
            "lng": -73.7498543
          }
        },
        "bounds": {
          "southwest": {
            "lat": 40.4773990,
            "lng": -74.2590900
          },
          "northeast": {
            "lat": 40.9175770,
            "lng": -73.7002720
          }
        }
      }
    }
  ]
}

Answer 7

我刚刚写的更简单一个:

public class JsonFormatter
{
    public static string Indent = "    ";

    public static string PrettyPrint(string input)
    {
        var output = new StringBuilder(input.Length * 2);
        char? quote = null;
        int depth = 0;

        for(int i=0; i<input.Length; ++i)
        {
            char ch = input[i];

            switch (ch)
            {
                case '{':
                case '[':
                    output.Append(ch);
                    if (!quote.HasValue)
                    {
                        output.AppendLine();
                        output.Append(Indent.Repeat(++depth));
                    }
                    break;
                case '}':
                case ']':
                    if (quote.HasValue)  
                        output.Append(ch);
                    else
                    {
                        output.AppendLine();
                        output.Append(Indent.Repeat(--depth));
                        output.Append(ch);
                    }
                    break;
                case '"':
                case '\'':
                    output.Append(ch);
                    if (quote.HasValue)
                    {
                        if (!output.IsEscaped(i))
                            quote = null;
                    }
                    else quote = ch;
                    break;
                case ',':
                    output.Append(ch);
                    if (!quote.HasValue)
                    {
                        output.AppendLine();
                        output.Append(Indent.Repeat(depth));
                    }
                    break;
                case ':':
                    if (quote.HasValue) output.Append(ch);
                    else output.Append(" : ");
                    break;
                default:
                    if (quote.HasValue || !char.IsWhiteSpace(ch)) 
                        output.Append(ch);
                    break;
            }
        }

        return output.ToString();
    }
}

必要的扩展:

    public static string Repeat(this string str, int count)
    {
        return new StringBuilder().Insert(0, str, count).ToString();
    }

    public static bool IsEscaped(this string str, int index)
    {
        bool escaped = false;
        while (index > 0 && str[--index] == '\\') escaped = !escaped;
        return escaped;
    }

    public static bool IsEscaped(this StringBuilder str, int index)
    {
        return str.ToString().IsEscaped(index);
    }

样本输出:

{
    "status" : "OK",
    "results" : [
        {
            "types" : [
                "locality",
                "political"
            ],
            "formatted_address" : "New York, NY, USA",
            "address_components" : [
                {
                    "long_name" : "New York",
                    "short_name" : "New York",
                    "types" : [
                        "locality",
                        "political"
                    ]
                },
                {
                    "long_name" : "New York",
                    "short_name" : "New York",
                    "types" : [
                        "administrative_area_level_2",
                        "political"
                    ]
                },
                {
                    "long_name" : "New York",
                    "short_name" : "NY",
                    "types" : [
                        "administrative_area_level_1",
                        "political"
                    ]
                },
                {
                    "long_name" : "United States",
                    "short_name" : "US",
                    "types" : [
                        "country",
                        "political"
                    ]
                }
            ],
            "geometry" : {
                "location" : {
                    "lat" : 40.7143528,
                    "lng" : -74.0059731
                },
                "location_type" : "APPROXIMATE",
                "viewport" : {
                    "southwest" : {
                        "lat" : 40.5788964,
                        "lng" : -74.2620919
                    },
                    "northeast" : {
                        "lat" : 40.8495342,
                        "lng" : -73.7498543
                    }
                },
                "bounds" : {
                    "southwest" : {
                        "lat" : 40.4773990,
                        "lng" : -74.2590900
                    },
                    "northeast" : {
                        "lat" : 40.9175770,
                        "lng" : -73.7002720
                    }
                }
            }
        }
    ]
}

Answer 8

All credits are to Frank Tzanabetis. However this is the shortest direct example, that also survives in case of empty string or broken original JSON string:

using Newtonsoft.Json;
using Newtonsoft.Json.Linq;

    ...
    try
    {
        return JToken.Parse(jsonString).ToString(Formatting.Indented);
    }
    catch
    {
        return jsonString;

Answer 9

只需使用JsonDocument和Utf8JsonWriter。无需第三方库。不需要反序列化的目标对象jsonString。

using System.IO;
using System.Text;
using System.Text.Json;

// other code ...

public string Prettify(string jsonString)
{
    using var stream = new MemoryStream();
    var document = JsonDocument.Parse(jsonString);
    var writer = new Utf8JsonWriter(stream, new JsonWriterOptions { Indented = true });
    document.WriteTo(writer);
    writer.Flush();
    return Encoding.UTF8.GetString(stream.ToArray());
}

Answer 10

这里已经有很多使用Newtonsoft.JSON的不错的答案，但是这里还有更多JObject.Parse与结合使用的答案ToString()，因为尚未提及：

var jObj = Newtonsoft.Json.Linq.JObject.Parse(json);
var formatted = jObj.ToString(Newtonsoft.Json.Formatting.Indented);