C输出因代码不同而不同

Question

#include <stdio.h>
#include <stdlib.h>

int main() {

    int* a[10];
    int* p = a;
    int i = 0;
    for (p = &a[0], i = 0; p < &a[10]; p++, i++)
    {
        *p = i;
    }
    for (int i = 0; i < 10; i++)
    {
        printf("%d\n", a[i]);
    }
}

使用eclipse在GCC上的输出:

0
2
4
6
8
10
12
14
16
18

使用visual studio输出:

0
1
2
3
4
5
6
7
8
9

为什么？

Answer 1

% gcc error.c -Wall -Wextra
error.c: In function ‘main’:
error.c:7:14: warning: initialization from incompatible pointer type [-Wincompatible-pointer-types]
     int* p = a;
              ^
error.c:9:12: warning: assignment from incompatible pointer type [-Wincompatible-pointer-types]
     for (p = &a[0], i = 0; p < &a[10]; p++, i++)
            ^
error.c:9:30: warning: comparison of distinct pointer types lacks a cast
     for (p = &a[0], i = 0; p < &a[10]; p++, i++)
                              ^
error.c:15:18: warning: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘int *’ [-Wformat=]
         printf("%d\n", a[i]);
                  ^

暗示:

int a[10]; // notice the lack of star here.