我一直在努力听起来很简单。我一直在尝试按下onpressed时获取按钮。尝试了几种组合器,但没有任何效果。有任何想法吗?
export default class JobScreen extends React.Component {
constructor(props) {
super(props);
}
static navigationOptions = ({navigation}) => ({
title: "Chat with"
});
onPressLearnMore(nav) {
// how do I update the title header
console.log("On Pressed" + nav)
}
render() {
const {navigate} = this.props.navigation;
return (
<View style={styles.container}>
<Button
onPress={() => {this.onPressLearnMore(navigate)}}
title="Learn More"
color="#841584"
/>
</View>
);
}
}
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由于navigationOptions可以访问该navigation对象,因此您可以在当前屏幕上使用设置一些参数this.props.navigation.setParam({ title: ‘some title’ }),然后navigationOptions像这样访问它
static navigationOptions = ({ navigation }) => {
const { state: { params = {} } } = navigation;
return {
title: params.title || ‘default title’,
};
}
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