Sea*_*404 11 javascript setstate ios reactjs react-native
我是iOS开发人员,目前正在开发一个实验性的React Native应用程序.我有以下代码,在屏幕上显示一个按钮和示例文本.
import React from 'react';
import { StyleSheet, Text, View , Button } from 'react-native';
export default class App extends React.Component {
constructor() {
super();
this.state = {sampleText: 'Initial Text'};
}
changeTextValue = () => {
this.setState({sampleText: 'Changed Text'});
}
_onPressButton() {
<Text onPress = {this.changeTextValue}>
{this.state.sampleText}
</Text>
}
render() {
return (
<View style={styles.container}>
<Text onPress = {this.changeTextValue}>
{this.state.sampleText}
</Text>
<View style={styles.buttonContainer}>
<Button
onPress={this._onPressButton}
title="Change Text!"
color="#00ced1"
/>
</View>
</View>
);
}
}
const styles = StyleSheet.create({
container: {
flex: 1,
backgroundColor: '#f5deb3',
alignItems: 'center',
justifyContent: 'center',
},
buttonContainer: {}
});
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上面的代码显示文本和按钮.
但是,当我单击该按钮时,应用程序崩溃而不是显示要显示的新文本.
我是React Native的新手,请指导我如何解决错误.
kle*_*ndi 20
您可以使用状态来保留默认文本,然后按下我们更新状态.
import React, { Component } from 'react'
import { View, Text, Button } from 'react-native'
export default class App extends Component {
state = {
textValue: 'Change me'
}
onPress = () => {
this.setState({
textValue: 'THE NEW TEXT GOES HERE'
})
}
render() {
return (
<View style={{paddingTop: 25}}>
<Text>{this.state.textValue}</Text>
<Button title="Change Text" onPress={this.onPress} />
</View>
)
}
}
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