将日期参数传递给本机查询

Question

用户可以根据出现值执行操作。当此值等于“ DAILY”时，我想检索最近24小时内尚未完成的所有日常操作。

有效的SQL查询：

SELECT distinct a.* FROM action as a LEFT OUTER JOIN history as h
ON a.id = h.action_id
AND h.user_id= <user> WHERE a.occurrence = 'DAILY' AND (h.id is NULL OR h.entry_date < TIMESTAMP 'yesterday')

等效的本机查询：

@Query(value = 
        "SELECT distinct a.* FROM action a "
        + "LEFT OUTER JOIN history h "
        + "ON a.id = h.action_id "
        + "AND h.user_id = :userId "
        + "WHERE a.occurrence='DAILY' AND (h.id IS NULL OR h.entry_date < :yesterday) ", nativeQuery = true)
public List<Action> findAllAvailableActions(@Param("userId") Long userId, @Param("yesterday") ZonedDateTime yesterday);

在我的服务中如何称呼它：

ZonedDateTime today = ZonedDateTime.now(ZoneOffset.UTC);
ZonedDateTime yesterday = today.minus(1,ChronoUnit.DAYS);
Long userId = userDTO.getId();
List<Action> result = actionRepositoryCustom.findAllAvailableActions(userId, yesterday);

但是，我在测试中确实得到了错误的结果（已返回的操作已返回）。恐怕这链接到date参数。在我的实体中，属性entry_date声明为ZoneDateTime。我究竟做错了什么 ？

休眠状态：5.2.4

Answer 1

您无法将 ZonedDateTime 传递到本机 SQL 查询中。您需要将其转换为日历：

@Query(value = 
    "SELECT distinct a.* FROM action a "
    + "LEFT OUTER JOIN history h "
    + "ON a.id = h.action_id "
    + "AND h.user_id = :userId "
    + "WHERE a.occurrence='DAILY' AND (h.id IS NULL OR h.entry_date < :yesterday)", nativeQuery = true)
public List<Action> findAllAvailableActions(@Param("userId") Long userId, @Param("yesterday") Calendar yesterday);

你可以这样转换你的 ZonedDateTime ：

public Calendar convertToDatabaseColumn(ZonedDateTime entityAttribute) {
    if (entityAttribute == null) {
        return null;
    }

    Calendar calendar = Calendar.getInstance();
    calendar.setTimeInMillis(entityAttribute.toInstant().toEpochMilli());
    calendar.setTimeZone(TimeZone.getTimeZone(entityAttribute.getZone()));
    return calendar;
}

这种方法的描述如下：链接