有没有办法将宏作为参数传递给宏?
就像是
%macro outer_macro(macro);
%do i=1 %to 5;
¯o
%end;
%mend outer_macro;
%macro inner_macro;
/* do something usefull */
%mend inner_macro;
%outer_macro(%inner_macro)
Run Code Online (Sandbox Code Playgroud)
当然,这个例子不起作用.
您可以使用宏引用来完成此操作.
您的示例的简单版本:
%macro outer_macro(macro);
%put Starting outer macro;
%unquote(¯o) /* %unquote removes the NRSTR escape characters */
%put Ending outer macro;
%mend outer_macro;
%macro inner_macro;
%put Starting inner macro;
proc print data=sashelp.class;
run;
%put Ending inner macro;
%mend inner_macro;
%outer_macro(%nrstr(%inner_macro)) /* %nrstr is execution-time quoting, so %inner_macro is passed and not treated as a macro until %unquote removes the quoting */
Run Code Online (Sandbox Code Playgroud)
要涉及类似循环的东西,你只需要确保所有东西都设置为采用循环迭代器 - 一种方法就是简单地用循环追加().
%macro outer_macro(macro);
%put Starting outer macro;
%do i = 1 %to 19;
%unquote(¯o)(n=&i.) /* resolves to %inner_macro(n=&i.) */
%end;
%put Ending outer macro;
%mend outer_macro;
%macro inner_macro(n=);
%put Starting inner macro;
proc print data=sashelp.class(obs=&n. firstobs=&n.);
run;
%put Ending inner macro;
%mend inner_macro;
%outer_macro(%nrstr(%inner_macro))
Run Code Online (Sandbox Code Playgroud)