PHP:多个foreach中的变量范围

Question

编辑:
在函数调用中使用$ i + 1解决了问题.

我在多个foreaches中使用变量时遇到了麻烦.当我尝试在foreach中调用函数时,问题就会出现.每当我这样做时,主循环的迭代器值突然为零(无论它在哪一圈),但是当我注释掉函数调用时,迭代器值再次显示为它.

有人能指出我在以下示例中访问变量的正确方向:

这应该是应有的

for($i=0; $i<3; $i++)
{
    echo $i; // 1, 2, 3
    foreach($something as $value)
    {
        echo $i; // main loop's iterator value
        foreach($value as $moreSomething)
        {
            echo $i; // main loop's iterator value 
        }
    }
}

但这不起作用,迭代器显示为0.

for($i=0; $i<3; $i++)
{
    echo $i; // 1, 2, 3
    foreach($something as $value)
    {
        echo $i; // 0
        foreach($value as $moreSomething)
        {
            echo $i; // 0
            $object->addStuff($i, $moreSomething); // i = 0, moreSomething is correct
        }
    }
}

编辑:我正在添加示例代码来重现问题.请注意,这是关于$ i的值的行为,而不是名称的正确顺序或类似的行为.我只关心为什么$ i的价值会突然改变.可能是我的逻辑,但要亲自看看

(当在addName()函数中使用$ i或$ b时,$ i的输出为000000000012,当使用$ a时,$ i的输出突然变为00000000001111111222)

class RockPaperScissors
{
    private $nameArray;

  // constructor
  function RockPaperScissors () 
  {
    $this->nameArray = array();
  }

  function addName($level, $name)
  {
    $this->nameArray[$level][] = $name;
  }

  function getNames($level)
  {
    $array = array();
    foreach ($this->nameArray as $key => $value)
    {
        if ($key == $level)
        {
            foreach ($value as $name)
            {
                $array[] = $name;
            }
        }
    }
    return $array;
  }

  function printArray()
  {
    print_r($this->nameArray);
  }
}

function getNewNames($name)
{
    $array = array();
    switch ($name)
    {
        case "Mickey":
            $array[] = "Morty";
            $array[] = "Ferdie";
            break;

        case "Donald":
            $array[] = "Houie";
            $array[] = "Dewey";
            $array[] = "Louie";
            break;

        case "Goofy":
            $array[] = "Gilbert";
            break;

        case "Morty":
            $array[] = "Morty-B";
            break;

        case "Ferdie":
            $array[] = "Ferdie-B";
            break;

        case "Houie":
            $array[] = "Houie-B";
            break;

        case "Dewey":
            $array[] = "Dewey-B";
            break;

        case "Louie":
            $array[] = "Louie-B";
            break;

        case "Gilbert":
            $array[] = "Gilbert-B";
            break;
    }

    return $array;
}

$MAX_LEVELS = 3;
$RPS = new RockPaperScissors();
$RPS->addName(0, "Mickey");
$RPS->addName(0, "Donald");
$RPS->addName(0, "Goofy");

$a = 0;
$b = 0;
for ($i=0; $i<$MAX_LEVELS; $i++)
{
    $namesFromRPS = $RPS->getNames($i);
    echo $i;
    foreach($namesFromRPS as $name)
    {
        echo $i;
        $newNames = getNewNames($name);
        foreach($newNames as $newName)
        {         
            echo $i;
            // try switching $i to $a or $b and notice the behaviour change of $i
            $RPS->addName($i, $newName);
        }
        $a++;
    }
    $b++;
}

//$RPS->printArray();

Answer 1

foreach 循环没有自己的范围.

预期这种方式的工作方式是:

Set $i to 0
 Enter the first foreach loop with `$i = 0`
  Enter the second foreach loop with `$i = 0`

Set $i to 1
 Enter the first foreach loop with `$i = 1`
  Enter the second foreach loop with `$i = 1`

etc.

我会打赌啤酒循环按预期工作,但$i到达时内圈没有任何关系1.