为什么方法不起作用？

Question

我正在编程计算器,当我选择第一个选项时,程序停止.我不能输入任何数字.我需要在代码中更改以使方法有效吗？我不知道自己要做什么.

main.cpp中:

#include "stdafx.h"
#include <iostream>
#include "Calculator.h"

using namespace std;

float Calculator::add()
{
    cout << "Enter 1 number: ";
    cin >> a;
    cout << "Enter 2 number: ";
    cin >> b;
    system("cls");

    cout << a + b << endl;

    return 0;
}

float Calculator::sub()
{
    cout << "Enter 1 number: ";
    cin >> a;
    cout << "Enter 2 number: ";
    cin >> b;
    system("cls");

    cout << a - b << endl;

    return 0;
}

float Calculator::mul()
{
    cout << "Enter 1 number: ";
    cin >> a;
    cout << "Enter 2 number: ";
    cin >> b;
    system("cls");

    cout << a*b << endl;

    return 0;
}

float Calculator::div()
{
    cout << "Enter 1 number: ";
    cin >> a;
    cout << "Enter 2 number: ";
    cin >> b;
    system("cls");

    cout << a / b << endl;

    return 0;
}

int main()
{
    int choose;

    Calculator k1;

    cout << "1.Add\n";
    cout << "2.Sub\n";
    cout << "3.Mul\n";
    cout << "4.Div\n";
    cout << "Choose: ";
    cin >> choose;

    if (choose == '1')
        k1.add();
    else if (choose == '2')
        k1.sub();
    else if (choose == '3')
        k1.mul();
    else if (choose == '4')
        k1.div();


    system("pause");
    return 0;
}

Calculator.h:

#pragma once
#ifndef Calculator_h
#define Calculator_h

class Calculator {
private:
    float a, b;
public:
    float add();
    float sub();
    float mul();
    float div();
};

#endif

Answer 1

您正在阅读选择为int:int choose;所以您必须将其视为一个:

if (choose == 1)
    k1.add();
else if (choose == 2)
    k1.sub();
else if (choose == 3)
    k1.mul();
else if (choose == 4)
    k1.div();

按要求说明:

if (choose == '1')

从句法上讲,这没有错,因为简单地说C++ 将char'1' 隐式地转换为其ASCII码,这是一个值为49的int.

你实际上是在做以下事情:if (choose == 49)而不是if (choose == 1)