Firebase在发布模式下找不到与对象一起序列化的属性

Bar*_*Ros 6 java android object release-mode firebase

我写了一个将实时位置数据推送到Firebase的方法:

private void writeNewMarker(int sessionType, String myUuid, String datetime, Location location) {
    locationToDB = new LocationFromAndroid();
    JSONObject jsonObjectCoords = new Coords(location.getLatitude() + "", location.getLongitude() + "", location.getAltitude() + "");
    locationToDB.setFinish("false");
    locationToDB.setLost("false");
    locationToDB.setCoords(jsonObjectCoords);
    locationToDB.setDistanceToGo("0");
    locationToDB.setHeading(location.getBearing() + "");
    locationToDB.setNauwkeurigheid(location.getAccuracy() + "");
    locationToDB.setSpeed(location.getSpeed() * 3.6 + "");
    locationToDB.setSpeed2(location.getSpeed() + "");
    locationToDB.setTimestamp(location.getTime() + "");
    locationToDB.setWp_user(myUuid);
    locationToDB.setSessionType(sessionType);
    locationToDB.setTitle(title);
    if(myUuid != null && datetime != null && locationToDB.getTitle() != null && !myUuid.isEmpty() && !datetime.isEmpty()) {
        databaseRef.child(myUuid + "-Android" + sessionType + datetime).setValue(locationToDB);
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当我在调试模式下构建应用程序时,它完全正常.但是,当我在Google Play的发布模式下构建它时,它会停止在此行上工作:

databaseRef.child(myUuid + "-Android" + sessionType + datetime).setValue(locationToDB);
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更具体一点:当我这样做时,一切都很好:

databaseRef.child(myUuid + "-Android" + sessionType + datetime).setValue("Test");
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它看起来像传递一个对象,因为在签名的APK中无法获得值?

错误: 异常com.google.firebase.database.DatabaseException:没有要在类上找到的序列化属性

Bar*_*Ros 14

添加-keepclassmembers class com.yourcompany.models.** { *; }proguard-rules.pro就可以了.

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