Kum*_*ish 13 java mysql hibernate jpa batch-insert
我试图使用Hibernate(JPA)在5秒内在MYSQL表中插入100,000行.我已经尝试过hibernate提供的每一个技巧,但仍然不能超过35秒.
第一次优化:我开始使用IDENTITY序列生成器,这导致插入60秒.我后来放弃了序列生成器并开始@Id自己通过阅读MAX(id)和使用AtomicInteger.incrementAndGet()自己分配字段来分配字段.这将插入时间减少到35秒.
第二次优化:我通过添加启用了批量插入
<prop key="hibernate.jdbc.batch_size">30</prop>
<prop key="hibernate.order_inserts">true</prop>
<prop key="hibernate.current_session_context_class">thread</prop>
<prop key="hibernate.jdbc.batch_versioned_data">true</prop>
到配置.我很震惊地发现批量插入绝对没有减少插入时间.现在还有35秒!
现在,我正在考虑尝试使用多个线程插入.任何人有任何指针?我应该选择MongoDB吗?
下面是我的配置:1.Hibernate配置`
<bean id="entityManagerFactoryBean" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.progresssoft.manishkr" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />
</property>
<property name="jpaProperties">
<props>
<prop key="hibernate.hbm2ddl.auto">${hibernate.hbm2ddl.auto}</prop>
<prop key="hibernate.dialect">${hibernate.dialect}</prop>
<prop key="hibernate.show_sql">${hibernate.show_sql}</prop>
<prop key="hibernate.format_sql">${hibernate.format_sql}</prop>
<prop key="hibernate.jdbc.batch_size">30</prop>
<prop key="hibernate.order_inserts">true</prop>
<prop key="hibernate.current_session_context_class">thread</prop>
<prop key="hibernate.jdbc.batch_versioned_data">true</prop>
</props>
</property>
</bean>
<bean class="org.springframework.jdbc.datasource.DriverManagerDataSource"
id="dataSource">
<property name="driverClassName" value="${database.driver}"></property>
<property name="url" value="${database.url}"></property>
<property name="username" value="${database.username}"></property>
<property name="password" value="${database.password}"></property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactoryBean" />
</bean>
<tx:annotation-driven transaction-manager="transactionManager" />
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`
`
@Entity
@Table(name = "myEntity")
public class MyEntity {
@Id
private Integer id;
@Column(name = "deal_id")
private String dealId;
....
....
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "timestamp")
private Date timestamp;
@Column(name = "amount")
private BigDecimal amount;
@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "source_file")
private MyFile sourceFile;
public Deal(Integer id,String dealId, ....., Timestamp timestamp, BigDecimal amount, SourceFile sourceFile) {
this.id = id;
this.dealId = dealId;
...
...
...
this.amount = amount;
this.sourceFile = sourceFile;
}
public String getDealId() {
return dealId;
}
public void setDealId(String dealId) {
this.dealId = dealId;
}
...
...
....
public BigDecimal getAmount() {
return amount;
}
public void setAmount(BigDecimal amount) {
this.amount = amount;
}
....
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
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`
`
@Service
@Transactional
public class ServiceImpl implements MyService{
@Autowired
private MyDao dao;
....
`void foo(){
for(MyObject d : listOfObjects_100000){
dao.persist(d);
}
}
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`4.道类:
`
@Repository
public class DaoImpl implements MyDao{
@PersistenceContext
private EntityManager em;
public void persist(Deal deal){
em.persist(deal);
}
}
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`
日志:`
DEBUG o.h.e.j.b.internal.AbstractBatchImpl - Reusing batch statement
18:26:32.906 [http-nio-8080-exec-2] DEBUG org.hibernate.SQL - insert into deal (amount, deal_id, timestamp, from_currency, source_file, to_currency, id) values (?, ?, ?, ?, ?, ?, ?)
18:26:32.906 [http-nio-8080-exec-2] DEBUG o.h.e.j.b.internal.AbstractBatchImpl - Reusing batch statement
18:26:32.906 [http-nio-8080-exec-2] DEBUG org.hibernate.SQL - insert into deal (amount, deal_id, timestamp, from_currency, source_file, to_currency, id) values (?, ?, ?, ?, ?, ?, ?)
18:26:32.906 [http-nio-8080-exec-2] DEBUG o.h.e.j.b.internal.AbstractBatchImpl - Reusing batch statement
18:26:32.906 [http-nio-8080-exec-2] DEBUG org.hibernate.SQL - insert into deal (amount, deal_id, timestamp, from_currency, source_file, to_currency, id) values (?, ?, ?, ?, ?, ?, ?)
18:26:32.906 [http-nio-8080-exec-2] DEBUG o.h.e.j.b.internal.AbstractBatchImpl - Reusing batch statement
18:26:32.906 [http-nio-8080-exec-2] DEBUG org.hibernate.SQL - insert into deal (amount, deal_id, timestamp, from_currency, source_file, to_currency, id) values (?, ?, ?, ?, ?, ?, ?)
18:26:32.906 [http-nio-8080-exec-2] DEBUG o.h.e.j.b.internal.AbstractBatchImpl - Reusing batch statement
18:26:32.906 [http-nio-8080-exec-2] DEBUG org.hibernate.SQL - insert into deal (amount, deal_id, timestamp, from_currency, source_file, to_currency, id) values (?, ?, ?, ?, ?, ?, ?)
18:26:32.906 [http-nio-8080-exec-2]
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......
DEBUG o.h.e.j.b.internal.AbstractBatchImpl - Reusing batch statement
18:26:34.002 [http-nio-8080-exec-2] DEBUG org.hibernate.SQL - insert into deal (amount, deal_id, timestamp, from_currency, source_file, to_currency, id) values (?, ?, ?, ?, ?, ?, ?)
18:26:34.002 [http-nio-8080-exec-2] DEBUG o.h.e.j.b.internal.AbstractBatchImpl - Reusing batch statement
18:26:34.002 [http-nio-8080-exec-2] DEBUG org.hibernate.SQL - insert into deal (amount, deal_id, timestamp, from_currency, source_file, to_currency, id) values (?, ?, ?, ?, ?, ?, ?)
18:26:34.002 [http-nio-8080-exec-2] DEBUG o.h.e.j.b.internal.AbstractBatchImpl - Reusing batch statement
18:26:34.002 [http-nio-8080-exec-2] DEBUG org.hibernate.SQL - insert into deal (amount, deal_id, timestamp, from_currency, source_file, to_currency, id) values (?, ?, ?, ?, ?, ?, ?)
18:26:34.002 [http-nio-8080-exec-2] DEBUG o.h.e.j.b.internal.AbstractBatchImpl - Reusing batch statement
18:26:34.002 [http-nio-8080-exec-2] DEBUG org.hibernate.SQL - insert into deal (amount, deal_id, timestamp, from_currency, source_file, to_currency, id) values (?, ?, ?, ?, ?, ?, ?)
18:26:34.002 [http-nio-8080-exec-2] DEBUG o.h.e.j.batch.internal.BatchingBatch - Executing batch size: 27
18:26:34.011 [http-nio-8080-exec-2] DEBUG org.hibernate.SQL - update deal_source_file set invalid_rows=?, source_file=?, valid_rows=? where id=?
18:26:34.015 [http-nio-8080-exec-2] DEBUG o.h.e.j.batch.internal.BatchingBatch - Executing batch size: 1
18:26:34.018 [http-nio-8080-exec-2] DEBUG o.h.e.t.i.jdbc.JdbcTransaction - committed JDBC Connection
18:26:34.018 [http-nio-8080-exec-2] DEBUG o.h.e.t.i.jdbc.JdbcTransaction - re-enabling autocommit
18:26:34.032 [http-nio-8080-exec-2] DEBUG o.s.orm.jpa.JpaTransactionManager - Closing JPA EntityManager [org.hibernate.jpa.internal.EntityManagerImpl@2354fb09] after transaction
18:26:34.032 [http-nio-8080-exec-2] DEBUG o.s.o.jpa.EntityManagerFactoryUtils - Closing JPA EntityManager
18:26:34.032 [http-nio-8080-exec-2] DEBUG o.h.e.j.internal.JdbcCoordinatorImpl - HHH000420: Closing un-released batch
18:26:34.032 [http-nio-8080-exec-2] DEBUG o.h.e.j.i.LogicalConnectionImpl - Releasing JDBC connection
18:26:34.033 [http-nio-8080-exec-2] DEBUG o.h.e.j.i.LogicalConnectionImpl - Released JDBC connection
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"
Kum*_*ish 14
在尝试了所有可能的解决方案后,我终于找到了一个在5秒内插入100,000行的解决方案
我试过的事情:
1)使用AtomicInteger通过自生成的ID替换hibernate /数据库的AUTOINCREMENT/GENERATED id
2)使用batch_size = 50启用batch_inserts
3)每次'batch_size'次数的persist()调用后刷新缓存
4)多线程(没试过这个)
最后有用的是使用本机多插入查询并在一个sql插入查询中插入1000行,而不是在每个实体上使用persist().为了插入100,000个实体,我创建了一个像这样的本机查询"INSERT into MyTable VALUES (x,x,x),(x,x,x).......(x,x,x)"[在一个sql插入查询中插入1000行]
现在插入100,000条记录大约需要3秒钟!所以瓶颈就是兽人本身!对于批量插入,似乎唯一有效的是本机插入查询!
您正在使用 Spring 来管理事务,但通过thread用作当前会话上下文来破坏它。当使用 Spring 来管理您的事务时,不要乱搞hibernate.current_session_context_class属性。去掉它。
不要使用DriverManagerDataSource像 HikariCP 这样合适的连接池。
在你的循环,你应该flush和clear在EntityManager定期,最好与您的批量大小。如果你没有一个持久化需要越来越长的时间,因为当你这样做时,Hibernate 会检查第一级缓存是否有脏对象,对象越多花费的时间就越多。使用 10 或 100 是可以接受的,但是为每个持久化检查 10000 个对象会造成损失。
——
@Service
@Transactional
public class ServiceImpl implements MyService{
@Autowired
private MyDao dao;
@PersistenceContext
private EntityManager em;
void foo(){
int count = 0;
for(MyObject d : listOfObjects_100000){
dao.persist(d);
count++;
if ( (count % 30) == 0) {
em.flush();
em.clear();
}
}
}
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