Laravel Guzzle 参数

Question

从 API 文档我有这个curl请求：

curl https://api.example.com/api/Jwt/Token ^
        -d Username="asd%40gmail.com" ^
        -d Password="abcd1234"

现在我正在尝试使用 Guzzle 库在 Laravel 5.1 中创建该请求，所以我写道：

 public function test()
    {

$client = new GuzzleHttp\Client();

$res = $client->createRequest('POST','https://api.example.com/api/Jwt/Token', [

    'form_params' => [
        'Username' => 'asd%40gmail.com',
        'Password' => 'abcd1234'
]
            ]);

$res = json_decode($res->getBody()->getContents(), true);

dd ($res);
}

但我收到此错误：

***ErrorException in Client.php line 126:
Argument 3 passed to GuzzleHttp\Client::request() must be of the type array,     string given, called in     /home/ibook/public_html/vendor/guzzlehttp/guzzle/src/Client.php on line 87 and defined***

问题是什么，我该如何解决该错误？

ps我也试过

$res = $client->createRequest('POST','https://api.example.com/api/Jwt/Token', 

    'form_params' => [
        'Username' => 'asd%40gmail.com',
        'Password' => 'abcd1234'

            ]);

但后来我得到：

syntax error, unexpected '=>' (T_DOUBLE_ARROW)

Answer 1

您正在调用该createRequest函数而不是request. 这应该有效：

$response = $client->request('POST', 'https://api.example.com/api/Jwt/Token', [
    'form_params' => [
        'Username' => 'asd%40gmail.com',
        'Password' => 'abcd1234'
    ]
]);

检查文档