Rag*_*S S 3 java oop equals hashmap java-8
//覆盖哈希码后无法获取hashmap中对象的值//这是我根据项名称生成hascode的item类
public class Item {
private String name;
private Long id;
private double price;
//Constructor
public Item(String name, Long id, double price) {
this.name = name;
this.id = id;
this.price = price;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public double getPrice() {
return price;
}
public void setPrice(double price) {
this.price = price;
}
//Generating hashcode based on name comparing if item id are //same
@Override
public int hashCode() {
return name.hashCode();
}
@Override
public boolean equals(Object obj) {
return ((Item) obj).id ==(id);
}
@Override
public String toString() {
return "Item {" +
" name='" + name + '\'' +
", id=" + id +
", price=" + price +
'}';
}
//Here there are items but when i pass the exact same item with exact //credentials i get null while checking how many items are there using Hashmap.
public class Warehouse {
Map<Item, Integer> itemList = new HashMap<>();
List<Drone> drones = new ArrayList<>();
private Drone drone;
private String sourceAddress;
private Address address;
public Warehouse(Address address) {
this.address = address;
Item item = new Item("PlayStation 4 pro", (long) 100, 42000);
Item item1 = new Item("X box one S", (long) 200, 40000);
Item item2 = new Item("Apple Macbook Pro", (long) 500, 82000);
Item item3 = new Item("Dell Xps Laptop", (long) 1000, 92000);
Item item4 = new Item("iPhone 7 plus", (long) 2000, 72000);
itemList.put(item, 10);
itemList.put(item1, 20);
itemList.put(item2, 40);
itemList.put(item3, 50);
itemList.put(item4, 20);
}
public Drone getDrone() {
return new Drone();
}
public void setDrone(Drone drone) {
this.drone = drone;
System.out.println("Drone # " + drone.getDroneID() + " has arrived at the warehouse " + address);
}
public Address getAddress() {
return address;
}
public ArrayList<Item> getItemList() {
return (ArrayList<Item>) itemList;
}
//Setting the item
public void setItem(Item item) {
Integer num = itemList.get(item);
if (num == null) {
num = 0;
}
this.itemList.put(item, ++num);
}
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//这是我面临的问题,如果我查询同一项的hashmap它返回null,Item甚至返回相同的hashcode
public Item removeItem(Item item) {
Integer num = itemList.get(item);
//## Issue is i get null in num
if(null!= num||num!=0 ){
itemList.put(item,num-1);
}
System.out.println(item);
return item;
}
}
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您的对象hashCode使用了该name属性,但您equals使用了该id属性.这违反了合同.equals返回true的对象必须具有相同的值hashCode.
HashMap使用两者hashCode并equals找到一个键.首先,它在HashMap基于的位置内找到一个bin hashCode.然后它会遍历bin中的所有条目,equals以找到您要查找的密钥.当hashCode不匹配时equals,您认为相等的两个对象可能会映射到不同的bin,因此使用map.contains(key)查找存储在其中的密钥Map将失败.
我认为id用作平等标准更有意义,所以我写道:
@Override
public int hashCode() {
return id.hashCode();
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (!(obj instanceof Item))
return false;
return ((Item) obj).id.equals(id);
}
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请注意,我用来equals比较ids.比较对象==(Long在你的情况下为s)通常是错误的.
此外,您可能希望equals通过obj在将其转换为之前检查其类型来使您的方法更安全,Item如果类型不匹配则返回false.
PS基于你的新代码,你有另一个问题:
这个条件:
if(null!= num||num!=0 )
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将是真(if num != null)或抛出NullPointerException(如果num是null).
因此,只能将item中Map,如果它已经在Map.目前尚不清楚所需的逻辑是什么,但它看起来并不正确.
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