rap*_*opo 3 javascript csv json
我有一个 CSV 文件,需要将其转换为 Javascript 对象/JSON 文件。哪一个并不重要,因为无论如何我都会在 JS 中处理数据,两者都可以。
例如:
name,birthday/day,birthday/month,birthday/year,house/type,house/address/street,house/address/city,house/address/state,house/occupants
Lily Haywood,27,3,1995,Igloo,768 Pocket Walk,Honolulu,HI,7
Stan Marsh,19,10,1987,Treehouse,2001 Bonanza Street,South Park,CO,2
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应该变成这样:
[
{
"name": "Lily Haywood",
"birthday": {
"day": 27,
"month": 3,
"year": 1995
},
"house": {
"type": "Igloo",
"address": {
"street": "768 Pocket Walk",
"city": "Honolulu",
"state": "HI"
},
"occupants": 7
}
},
{
"name": "Stan Marsh",
"birthday": {
"day": 19,
"month": 10,
"year": 1987
},
"house": {
"type": "Treehouse",
"address": {
"street": "2001 Bonanza Street",
"city": "South Park",
"state": "CO"
},
"occupants": 2
}
}
]
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这就是我想出的:
function parse(csv){
function createEntry(header){
return function (record){
let keys = header.split(",");
let values = record.split(",");
if (values.length !== keys.length){
console.error("Invalid CSV file");
return;
}
for (let i=0; i<keys.length; i++){
let key = keys[i].split("/");
let value = values[i] || null;
/////
if (key.length === 1){
this[key] = value;
}
else {
let newKey = key.shift();
this[newKey] = this[newKey] || {};
//this[newKey][key[0]] = value;
if (key.length === 1){
this[newKey][key[0]] = value;
}
else {
let newKey2 = key.shift();
this[newKey][newKey2] = this[newKey][newKey2] || {};
this[newKey][newKey2][key[0]] = value;
//if (key.length === 1){}
//...
}
}
/////
}
};
}
let lines = csv.split("\n");
let Entry = createEntry(lines.shift());
let output = [];
for (let line of lines){
entry = new Entry(line);
output.push(entry);
}
return output;
}
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我的代码可以工作,但是它有一个明显的缺陷:对于它进入的每一层(例如house/address/street),我必须手动编写重复的if / else语句。
有没有更好的写法呢?我知道这涉及某种递归或迭代,但我似乎不知道如何实现。
我已经搜索过所以但大多数问题似乎都是用Python而不是JS来做的。
我希望尽可能在普通 JS 中完成此操作,而不需要任何其他库。
通过递归创建Object就可以达到预期的结果。
看下面的代码:
var csv = [
"name,birthday/day,birthday/month,birthday/year,house/type,house/address/street,house/address/city,house/address/state,house/occupants",
"Lily Haywood,27,3,1995,Igloo,768 Pocket Walk,Honolulu,HI,7",
"Stan Marsh,19,10,1987,Treehouse,2001 Bonanza Street,South Park,CO,2"
];
var attrs = csv.splice(0,1);
var result = csv.map(function(row) {
var obj = {};
var rowData = row.split(',');
attrs[0].split(',').forEach(function(val, idx) {
obj = constructObj(val, obj, rowData[idx]);
});
return obj;
})
function constructObj(str, parentObj, data) {
if(str.split('/').length === 1) {
parentObj[str] = data;
return parentObj;
}
var curKey = str.split('/')[0];
if(!parentObj[curKey])
parentObj[curKey] = {};
parentObj[curKey] = constructObj(str.split('/').slice(1).join('/'), parentObj[curKey], data);
return parentObj;
}
console.log(result);Run Code Online (Sandbox Code Playgroud)
.as-console-wrapper{max-height: 100% !important; top:0}Run Code Online (Sandbox Code Playgroud)
constructObj()函数基本上通过查看列名来递归地构造结果对象,因此如果列名中包含类似内容,/它将house/address/street按名称在对象中创建一个键house,然后递归地调用自身以获取字符串 ie 中的其余剩余键address/street/。/当字符串中不再剩下任何内容时,递归结束,然后它只是分配该键中的值并返回结果对象。