Ala*_*l P 1 sql oracle hibernate jpa jpql
我有一个名为的表CUSTOMER,其中包含 100 多个 COLOUMNS。但我只想选择我在 POJO 中指定的 6 列:
实体 POJO:
@Entity
@Data
@Table(name = "CUSTOMER")
public class CustomerEntity {
@Id
@Column(name = "C_ID")
private String customerId;
@Id
@Column(name = "C_KEY")
private String customerKey;
@Column(name = "NAME")
private String name;
@Column(name = "FIRST_NAME")
private String firstName;
@Column(name = "LAST_NAME")
private String lastName;
@Column(name = "AGE")
private String age;
}
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本机查询:
String query = "select * from CUSTOMER where (C_ID= '1' AND C_KEY= '12') OR (C_ID= '1' AND C_KEY= '13')) AND AGE>25";
Query q = e.createNativeQuery(query,CustomerEntity.class);
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[编辑:出于使用本机查询的原因]
选择 Native Query 的原因:
复杂逻辑:
SELECT * FROM (
SELECT row_number() over(order by C_ID, C_KEY) RN, FEW-COLUMNS(
SELECT * FROM BOOK
WHERE (C_ID, C_KEY) IN (customerId1, customerKey1)
(customerId2, customerKey2)
(customerId3, customerKey3)
.....
(customerIdn, customerKeyn) AND ROWNUM <= 340
)WHERE RN BETWEEN anyNumber and anyNumber
)ORDER BY DESC RN;
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问题:
由于它是一个namedQuery,我无法将查询作为
String query = "select cu from CustomerEntity cu where ((cu.customerId = '1' AND cu.customerKey = '12') or (cu.customerId = '1' AND cu.customerKey = '13') AND cu.age > 25)";
如果我使用这个查询,我会得到ORA -00947表或视图不存在异常。
您必须使用别名才能使其正常工作。否则持久化提供者将不知道如何执行匹配:
select c_id as customerId, c_key as customerKey...
from CUSTOMER
where ...
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别名应该与您映射到的实体类的相应字段名称完全相同。