我正在使用的 Rest API 有一个名为 Api-Key 的新字段。这不是有效的 C# 字段名称,因此我想知道是否有不同的方式来构建主体。
var client = new RestClient("https://TestWeb");
var request = new RestRequest("login", Method.POST);
request.AddHeader("Content-type", "application/json");
request.AddJsonBody(
new {
credentials =
new
{
username = "Uname",
password = "password",
Api-Key = "apikey"
} });
Run Code Online (Sandbox Code Playgroud)
由于RestSharp使用默认的 Json 序列化器SimpleJson,据我所知,它不支持属性来更改序列化行为,所以我会:
安装为 NuGet 包Newtonsoft Json,以便使用其JsonProperty属性。
定义一个类来提供身份验证对象,如下所示:
public class AuthenticationInfos
{
[JsonProperty(PropertyName = "username")]
public string Username { get; set; }
[JsonProperty(PropertyName = "password")]
public string Password { get; set; }
[JsonProperty(PropertyName = "Api-Key")]
public string ApiKey { get; set; }
}
Run Code Online (Sandbox Code Playgroud)(关键部分在这里[JsonProperty(PropertyName = "Api-Key")],您告诉序列化程序使用该名称序列化该属性,这作为 C# 变量是无效的)
使用Newtonsoft Json序列化来序列化body请求:
var client = new RestClient("https://TestWeb");
var request = new RestRequest("login", Method.POST);
request.AddHeader("Content-type", "application/json");
var body = new
{
credentials =
new AuthenticationInfos()
{
Username = "Uname",
Password = "password",
ApiKey = "myApiKey"
}
};
var serializedBody = JsonConvert.SerializeObject(body);
request.AddParameter("application/json", serializedBody, ParameterType.RequestBody);
Run Code Online (Sandbox Code Playgroud)身体会是这样的:
{
"credentials":
{
"username": "Uname",
"password": "password",
"Api-Key": "myApiKey"
}
}
Run Code Online (Sandbox Code Playgroud)
当然,在接收消息时,您必须在反序列化阶段进行相同的操作。