setState用于嵌套对象

Question

我有一个嵌套对象作为状态,我有一个组件中的表单.我想每次用户在表单中输入内容时更新状态,并避免为每个输入创建许多函数,我正在考虑使用switch创建单个函数.

1. 用开关创建单个功能是个好主意吗？
2. 如何更新对象的单个嵌套元素？

我尝试使用以下代码但它不起作用:

class App extends Component {
  constructor(props) {
      super(props)
      this.state = {
        minutes: null,
        interests: {
          business: false,
          code: false,
          design: false
        },
        errors: []
      }
  }

  updatePreferences = (preferenceName, enteredValue) => {
    switch (preferenceName) {
      case preferenceName === "minutes":
        this.setState({minutes: enteredValue})
        return
      case preferenceName === "business":
        this.setState({interests.business: !this.state.interests.business})
        return
      case default:
        return
    }

  }
}

Answer 1

当然你可以使用switch,没有错误的AFAIK.

并使用更新嵌套对象setState.查看示例

  updatePreferences = (preferenceName, enteredValue) => {
     switch (preferenceName) {
      case preferenceName === "minutes":
        this.setState({minutes: enteredValue});
        return
      case preferenceName === "business":
        this.setState({...this.state, interests: {
          ...this.state.interests,
          business: !this.state.interests.business
        }});
        return
      default:
        return
    }

  }