Tim*_*mur 2 sql oracle ddl cascade foreign-keys
我目前正在使用 Oracle SQL Developer 编写数据库,我想对我的外键使用 ON DELETE CASCADE,但它显然不起作用。以下是有关声明。您可能会注意到没有更多的表,只有这两个用于测试。
CREATE TABLE pizza
( size NUMBER(3),
price NUMBER(5,2),
CONSTRAINT pk_pizza PRIMARY KEY (size, price)
);
CREATE TABLE pizzacondiment
( condiment VARCHAR(30),
pizzasize NUMBER(3),
pizzaprice NUMBER(5,2),
CONSTRAINT pk_condiments PRIMARY KEY (condiment, pizzasize, pizzaprice)
CONSTRAINT fk_condiments_pizza FOREIGN KEY (pizzasize, pizzaprice)
REFERENCES pizza (size, price)
ON DELETE CASCADE;
);
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现在,当我想放下桌上披萨时,输出说:
CREATE TABLE pizza
( size NUMBER(3),
price NUMBER(5,2),
CONSTRAINT pk_pizza PRIMARY KEY (size, price)
);
CREATE TABLE pizzacondiment
( condiment VARCHAR(30),
pizzasize NUMBER(3),
pizzaprice NUMBER(5,2),
CONSTRAINT pk_condiments PRIMARY KEY (condiment, pizzasize, pizzaprice)
CONSTRAINT fk_condiments_pizza FOREIGN KEY (pizzasize, pizzaprice)
REFERENCES pizza (size, price)
ON DELETE CASCADE;
);
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ON DELETE CASCADE适用于行级DML操作,但不会影响DDLlike DROP。我将添加一个示例,说明如何ON DELETE应用然后查看可以对 drop 语句进行的更改,以断开之间的链接pizza,pizzacondiment但将孤立对象pizzacondiment留在可查询状态。
创建表后:
CREATE TABLE PIZZA
(
"SIZE" NUMBER(3),
PRICE NUMBER(5, 2),
CONSTRAINT PK_PIZZA PRIMARY KEY ("SIZE", PRICE)
);
CREATE TABLE PIZZACONDIMENT
(
CONDIMENT VARCHAR(30),
PIZZASIZE NUMBER(3),
PIZZAPRICE NUMBER(5, 2),
CONSTRAINT PK_CONDIMENTS PRIMARY KEY (CONDIMENT, PIZZASIZE, PIZZAPRICE),
CONSTRAINT FK_CONDIMENTS_PIZZA FOREIGN KEY (PIZZASIZE, PIZZAPRICE)
REFERENCES PIZZA ("SIZE", PRICE)
ON DELETE CASCADE
);
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并添加一些测试数据:
INSERT INTO PIZZA VALUES (11,1.25);
INSERT INTO PIZZA VALUES (219,111.11);
INSERT INTO PIZZA VALUES (50,7.50);
INSERT INTO PIZZACONDIMENT VALUES ('Spinach',50,7.50);
INSERT INTO PIZZACONDIMENT VALUES ('Peppers',50,7.50);
INSERT INTO PIZZACONDIMENT VALUES ('Onions',50,7.50);
INSERT INTO PIZZACONDIMENT VALUES ('Tomatoes',219,111.11);
INSERT INTO PIZZACONDIMENT VALUES ('Mushrooms',11,1.25);
INSERT INTO PIZZACONDIMENT VALUES ('Olives',11,1.25);
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ON DELETE CASCADE当我们删除 size=11 的披萨时,我们可以看到实际效果:
SELECT COUNT(*) AS CONDIMENT_COUNT FROM PIZZACONDIMENT WHERE PIZZASIZE = 11;
CONDIMENT_COUNT
2
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然后制作delete:
DELETE FROM PIZZA WHERE "SIZE" = 11;
1 row deleted.
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并再次检查子表:
SELECT COUNT(*) AS CONDIMENT_COUNT FROM PIZZACONDIMENT WHERE PIZZASIZE = 11;
CONDIMENT_COUNT
0
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正如您所提到的,您希望DROP使用PIZZA表格但留下一个孤儿PIZZACONDIMENT,您可以通过调整DROP语法来做到这一点,使用CASCADE CONSTRAINTS. 这将删除任何会阻止DROP, 留下孤立子表的外键。
DROP TABLE PIZZA CASCADE CONSTRAINTS;
Table PIZZA dropped.
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pizzacondiment 是孤立的但仍然可用:
SELECT * FROM PIZZACONDIMENT WHERE CONDIMENT = 'Spinach';
CONDIMENT PIZZASIZE PIZZAPRICE
Spinach 50 7.5
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