Tug*_*ain 5 javascript ecmascript-6
为什么导出的箭头函数不保留其名称,是否有办法让它们这样做?
给出如下的ES6模块:
myModule.js
export function doSomeWork1() {
}
export const doSomeWork2 = () => {
};
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如果我然后将它们导入到另一个文件中,那么导出的函数会保留其名称,而箭头函数则不会.
example.js
import { doSomeWork1, doSomeWork2 } from './myModule';
console.log('doSomeWork1...');
console.log(doSomeWork1);
console.log(doSomeWork1.name); // name is retained
console.log('doSomeWork2...');
console.log(doSomeWork2);
console.log(doSomeWork2.name); // name is NOT retained
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输出:
doSomeWork1...
[Function: doSomeWork1]
doSomeWork1
doSomeWork2...
[Function]
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如果我在ES6模块中声明一个箭头函数而不导出它并直接在该文件中打印它确实保留了它的名字.
myModule.js
const doSomeWork3 = () => {
};
console.log('doSomeWork3...');
console.log(doSomeWork3);
console.log(doSomeWork3.name); // name is retained
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输出:
doSomeWork3...
[Function: doSomeWork3]
doSomeWork3
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