如何使用for-loop合并两个文件,if-else？

Question

从以下数据:

data01 =

pos     ids      sample1_value   sample2_value
2969    a:b:c    12:13:15        12:13:15
3222    a:b:c    13:13:16        21:33:41
3416    a:b:c    19:13:18        21:33:41
5207    a:b:c    11:33:41        91:33:41
5238    a:b:c    21:13:45        31:27:63
5398    a:b:c    31:27:63        28:63:41
5403    a:b:c    15:7:125        71:33:41
5426    a:b:c    12:13:25        82:25:14
5434    a:b:c    12:17:15        52:33:52

说我为每个样本计算了另一个id(d)值,但不是在每一行中.

data02 = 

pos     ids      sample1_value    sample2_value
2969    d        21               96
3416    d        52               85
5207    d        63               85
5398    d        27               52
5403    d        63               52
5434    d        81               63

问题:

我想为每个样本的每一行写下d的这个值.

是否可以使用for循环写回值？

预期最终产出:

pos     ids       sample1_value    sample2_value
2969    a:b:c:d   12:13:15:21      12:13:15:.
3222    a:b:c:d   13:13:16:.       21:33:41:.
3416    a:b:c:d   19:13:18:52      21:33:41:.
................................
.......................... in the same way as above

我只为sample01尝试了以下代码:

data01 = open('data01.txt', 'r')
header01 = data01.readline()
data01 = data01.read().rstrip('n').split('\n')

# similar code for data02

data01_new = open('data01_new.txt', 'w')
data01_new.write(header01 + '\n')


for lines in data01:
    values01 = lines.split('\t')
    pos01 = values01[0]
    ids01 = values01[1]
    sample1_val01 = values01[2]

    for lines in data02:
        values02 = lines.split('\t')
        pos02 = values02[0]
        ids02 = values02[1]
        sample1_val02 = values02[2]

        if pos01 == pos02:
            data01_update = open('data01_new.txt', 'a')
            data01_update.write('\t'.join(pos1, (ids01+':'+ids02), sample1_val01+':'+sample1_val02)

        else:
            data01_update = open('data01_new.txt', 'a')
            data01_update.write('\t'.join(pos1, (ids01+':'+ids02), sample1_val01+':'+'.')

• 据我所知,嵌套循环使用文件大小的乘积浪费了大量时间.
• 我的if/else逻辑用匹配更新行,但后来由不匹配覆盖.

是否可以使用for-loop and if-else？

如果没有,我如何使用熊猫来解决这个问题？

Answer 1

这是一种方法,首先合并pos上的两个数据,然后加入id,sample1和sample 2,最后只使用所需的列

data = data1.merge(data2, on = 'pos',how = 'outer').fillna('.')

data['ids'] = data['ids_x'] + ':'+ data['ids_y']
data['sample1_value'] = data['sample1_value_x'].astype(str) + ':'+ 
data['sample1_value_y'].astype(str)
data['sample2_value'] = data['sample2_value_x'].astype(str) + ':'+ 
data['sample2_value_y'].astype(str)
data = data[['pos', 'ids', 'sample1_value', 'sample2_value']]


    pos     ids     sample1_value   sample2_value
0   2969    a:b:c:d 12:13:15:21.0   12:13:15:96.0
1   3222    a:b:c:. 13:13:16:.      21:33:41:.
2   3416    a:b:c:d 19:13:18:52.0   21:33:41:85.0
3   5207    a:b:c:d 11:33:41:63.0   91:33:41:85.0
4   5238    a:b:c:. 21:13:45:.      31:27:63:.
5   5398    a:b:c:d 31:27:63:27.0   28:63:41:52.0
6   5403    a:b:c:d 15:7:125:63.0   71:33:41:52.0
7   5426    a:b:c:. 12:13:25:.      82:25:14:.
8   5434    a:b:c:d 12:17:15:81.0   52:33:52:63.0