Mysql左连接Group By和Between

Question

我无法创建一个选择查询,该查询将检索游戏中不存在的所有用户ID以及日期之间的可用性.

示例:检索不在日期2017-08-10和之间的所有用户2017-08-12.

得到 [3 , 4, 5]

用户

| Id | Name     |
| 1  | Jonh     |
| 2  | Mark     |
| 3  | Caroline |
| 4  | David    |
| 5  | George   |

游戏

| Id | User_Id  | Start_Date | End_Date   |
| 1  | 1        | 2017-06-01 | 2017-06-01 |
| 2  | 1        | 2017-08-12 | 2017-08-13 |
| 3  | 4        | 2017-08-13 | 2017-08-14 |

可用性

| Id | User_Id | Start_Date | End_Date   |
| 1  | 1       | 2017-05-01 | 2017-05-25 |
| 1  | 2       | 2017-08-10 | 2017-08-17 |
| 1  | 3       | 2017-06-20 | 2017-07-10 |

我正在使用Laravel 5.4,但如果答案是Raw或Eloquent,我会很高兴的.

Answer 1

在 SQL 中，您可以使用NOT EXISTS：

select *
from users u
where not exists (
        select 1
        from games g
        where u.id = g.user_id
            and (
                g.start_date between '2017-08-10' and '2017-08-12'
                or g.end_date between '2017-08-10' and '2017-08-12'
                )
        )
    and not exists (
        select 1
        from Availability a
        where u.id = a.user_id
            and (
                a.start_date between '2017-08-10' and '2017-08-12'
                or a.end_date between '2017-08-10' and '2017-08-12'
                )
        );

演示

另一种使用方法LEFT JOIN是：

select distinct u.*
from t_users u
left join games g on u.id = g.user_id
    and (g.start_date between '2017-08-10' and '2017-08-12'
        or g.end_date between '2017-08-10' and '2017-08-12')
left join availability a on u.id = a.user_id
    and (a.start_date between '2017-08-10' and '2017-08-12'
        or a.end_date between '2017-08-10' and '2017-08-12')
where g.user_id is null and a.user_id is null;

演示