<?php
namespace App\Http\Models;
use Illuminate\Database\Eloquent\Model;
use Sofa\Eloquence\Eloquence;
use Sofa\Eloquence\Mappable;
class User extends Model
{
use Eloquence, Mappable;
public $id;
public $name
}
$data= User::select('distinct User.name')->join('Member as m','User.id','m.userId')->whereRaw('User.name is not null')->get();
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我想避免一直使用表名,而是想使用别名.
您可以使用此Model::from方法
class User extends Model
{
use Eloquence, Mappable;
public $id;
public $name
}
$data= User::from('User as u')
->select('distinct u.name')
->join('Member as m','u.id','m.userId')
->whereRaw('u.name is not null')
->get();
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