输入是;
"AbrAcadAbRa"
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输出应该是;
["AbrA", "brAc", "rAca", "Acad", "cadA", "adAb", "dAbR", "AbRa]
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这是我到目前为止所尝试过的,没有成功;
public static void main(String[] args) {
// TODO Auto-generated method stub
String str = "AbrAcadAbRa";
int length = 4;
String subString = "";
for (int i = 0; i < length; i++) {
subString = str.substring(i, length);
System.out.println(subString);
str = str.substring(i);
}
}
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它给出了错误的输出;
["AbrA", "brA", "Ac", "d"]
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迭代字符串的逻辑是不正确的,因此是您当前的结果.我在下面使用的逻辑是遍历输入字符串的整个长度,但是需要很多空间来确保可以采用适当的长度子字符串.然后,在每次迭代中,打印出一个length子字符串.
public static void main(String args[]) {
String str = "AbrAcadAbRa";
int length = 4;
String subString = "";
// iterate over the length of the input, offset by the substring length
for (int i = 0; i < str.length()-length+1; i++) {
subString = str.substring(i, i+length);
System.out.println(subString);
// this is wrong; don't modify the original string
//str = str.substring(i);
}
}
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输出:
AbrA
brAc
rAca
Acad
cadA
adAb
dAbR
AbRa
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在这里演示:
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