如何在 react-router v4 中保留查询参数

Dmi*_*gin 16 javascript reactjs react-router react-router-v4

用户登录后重定向到我的应用程序(Java 上的服务器),他们有 url,看起来像这样 http://10.8.0.29:8083/html/?locale=RU&token=1c5c71f2-dcda-4a51-8cf6-f8f6ff1031d0&returnTo=http ://10.8.0.23:8080/

(带有一些参数,html - 是源所在的文件夹)。在我的应用程序上导航时,我需要保留这些参数。到目前为止,我没有找到任何简单的解决方案,除了这个如何在保留初始查询参数的同时使用 react-router 重定向?老问题,所以我再次提出这个问题,希望如此。提前致谢。

mix*_*xel 13

我已经分享了我的解决方案在对您的问题的评论中的 react-router v3。

以下是我对 react-router v4 的解决方案。

使用以下createPreserveQueryHistory函数来覆盖history.pushhistory.replace方法,以便它们保留指定的查询参数:

import queryString from 'query-string';
import {createBrowserHistory} from 'history'

function preserveQueryParameters(history, preserve, location) {
    const currentQuery = queryString.parse(history.location.search);
    if (currentQuery) {
        const preservedQuery = {};
        for (let p of preserve) {
            const v = currentQuery[p];
            if (v) {
                preservedQuery[p] = v;
            }
        }
        if (location.search) {
            Object.assign(preservedQuery, queryString.parse(location.search));
        }
        location.search = queryString.stringify(preservedQuery);
    }
    return location;
}

function createLocationDescriptorObject(location, state) {
    return typeof location === 'string' ? { pathname: location, state } : location;
}

function createPreserveQueryHistory(createHistory, queryParameters) {
    return (options) => {
        const history = createHistory(options);
        const oldPush = history.push, oldReplace = history.replace;
        history.push = (path, state) => oldPush.apply(history, [preserveQueryParameters(history, queryParameters, createLocationDescriptorObject(path, state))]);
        history.replace = (path, state) => oldReplace.apply(history, [preserveQueryParameters(history, queryParameters, createLocationDescriptorObject(path, state))]);
        return history;
    };
}

const history = createPreserveQueryHistory(createBrowserHistory, ['locale', 'token', 'returnTo'])();
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然后在路由器定义中使用它:

<Router history={history}>
    ...
</Router>
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对于那些使用 TypeScript 的人

import {History, LocationDescriptor, LocationDescriptorObject} from 'history'
import queryString from 'query-string'
import LocationState = History.LocationState

type CreateHistory<O, H> = (options?: O) => History & H

function preserveQueryParameters(history: History, preserve: string[], location: LocationDescriptorObject): LocationDescriptorObject {
    const currentQuery = queryString.parse(history.location.search)
    if (currentQuery) {
        const preservedQuery: { [key: string]: unknown } = {}
        for (let p of preserve) {
            const v = currentQuery[p]
            if (v) {
                preservedQuery[p] = v
            }
        }
        if (location.search) {
            Object.assign(preservedQuery, queryString.parse(location.search))
        }
        location.search = queryString.stringify(preservedQuery)
    }
    return location
}

function createLocationDescriptorObject(location: LocationDescriptor, state?: LocationState): LocationDescriptorObject {
    return typeof location === 'string' ? {pathname: location, state} : location
}

export function createPreserveQueryHistory<O, H>(createHistory: CreateHistory<O, H>,
                                                 queryParameters: string[]): CreateHistory<O, H> {
    return (options?: O) => {
        const history = createHistory(options)
        const oldPush = history.push, oldReplace = history.replace
        history.push = (path: LocationDescriptor, state?: LocationState) =>
            oldPush.apply(history, [preserveQueryParameters(history, queryParameters, createLocationDescriptorObject(path, state))])
        history.replace = (path: LocationDescriptor, state?: LocationState) =>
            oldReplace.apply(history, [preserveQueryParameters(history, queryParameters, createLocationDescriptorObject(path, state))])
        return history
    }
}
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Kaj*_*nus 9

在 React-Router 4.3(不确定早期版本)中,如果你有一个<Route>上面的,这样的东西应该可以工作:(这是在打字稿中)

Route({ path: ..., render: (props) => function() {
  Redirect({ ...,
      to: { pathname: ... search: props.location.search, ... }})
});
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说明:您使用标签的render: (props) => ....属性<Route>,而不是component: ...,因为render给了您props,因此<Redirect>您可以props.location.search在其中使用并以这种方式访问​​当前查询参数,并在重定向中重用。

如果没有<Route>以上,也许你不能。我只是在这里问:如何在 React-Router 4 <Switch><Redirect> 中保留查询字符串和哈希片段?


小智 2

它可以与react-router的useLocation钩子一起正常工作,请尝试以下操作

import { Link, useLocation } from 'react-router-dom';
    
function CustomPage() {

      const { search } = useLocation();
    
      return (
        <>
          <p>Preserve the query params?</p>
          <Link to={`/your-next-location${search}`}>Next link</Link>
        </>
      );
 }
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或者通过推送方式进行路线导航

 import { useHistory, useLocation } from 'react-router-dom';
 /*...
   .
   .
 ...*/
 const history = useHistory();
 const { search } = useLocation();
 /*...
   .
   .
 ...*/
 history.push({pathname:`/your-next-location${search}`});
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