Webpack:在窗口中导出到现有模块

Question

我的目标是使用Webpack将隔离的组件导出到假定的全局对象中.

的index.html

<script>
   var MyApp = window.MyApp || {};
   MyApp.something = MyApp.something || {};
</script>
<script src="my-isolated-module.js"></script>

//
// other modules/components loaded here...
//

<script>
   MyApp.something.myIsolatedModule.run();
</script>

在上面的例子中,我假设有一个全局对象/模块,它有一个属性something,它将附加其他模块.所以我想将我的孤立模块附加到全局MyApp.something对象而不破坏任何一个MyApp或MyApp.something.

webpack.config.js

var webpack = require('webpack');
var UglifyJsPlugin = require('webpack/lib/optimize/UglifyJsPlugin');

module.exports = {
    target: 'web',
    context: __dirname + '/src/',
    entry: './main.jsx',
    output: {
        path: __dirname + '/dist/',
        filename: 'app.bundle.js',
        library: 'something',
        libraryTarget: 'var'
    },
    resolve: {
        extensions: ['', '.js', '.jsx']
    },
    module: {
        loaders: [
            {test: /\.jsx$/, loader: '../node_modules/jsx-loader'}
        ]
    },
    externals: {
        react: {
            root: 'React',
            commonjs: 'react',
            commonjs2: 'react',
            amd: 'react'
        }
    },

    plugins: [
        new UglifyJsPlugin()
    ]
};

SRC/main.jsx

module.exports = {
    myIsolatedModule: require('./MyIsolatedModule')
};

我已经尝试将Webpack设置output.libraryTarget为每个可能的值(请参阅http://webpack.github.io/docs/configuration.html#output-librarytarget),并尝试使用其值以output.library包含直接命名空间用我的模块.什么都没有,因为我想...

Answer 1

output.library 可以是如下数组:

output: {
    library: ['MyApp', 'something']
}

这将在窗口上创建一个对象,window.MyApp.something或者window.MyApp如果它已经存在则将其添加到该对象.