将列值映射到spark中的数字类型

Anu*_*hit 4 scala apache-spark

我有一个火花的df,如下结构:

amount gender status
1000   male   married
1313   female single
1000   male   married
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基本上我想创建一个性别是数字的新列

amount gender status  gender_num
1000   male   married 1
1313   female single  2
1000   male   married 1
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我厌倦了以下几点:

  val gender = df.gender

  val gender_num = gender match {
case male => 1
case female => 2
}
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我收到以下错误:

<console>:125: error: value pa_gender_category is not a member of org.apache.spark.sql.DataFrame
val gender = data.pa_gender_category
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我知道有一个stringtoindex函数,但我想手动执行此操作

T. *_*ęda 9

使用 withColumn

val input = // load input DataFrame
val withGender = input.withColumn("gender_num", when($"gender" === "female", 2).otherwise(1))
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您可以链接更多选项:

val withGender = input.withColumn("gender_num", when($"gender" === "female", 2).when($"gender" == "other", 3).otherwise(1))
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你也可以在Akash的答案中使用UDF.请注意,有时UDF无法像内置函数那样进行优化,但它们可以更具可读性