(子)组内的Oracle Rank()

Question

我试图在一个小组内获得正确的排名,并且结果有问题.我需要在每次基于时间戳更改组时获得排名.

例如,使用此表:

create table syntrans (
    transid     number,
    launchtime  timestamp,
    status      varchar2(10)
);

insert into syntrans values ( 1, '19-APR-17 07.34.05.824875 PM','FAIL');
insert into syntrans values (  1, '19-APR-17 07.34.06.828753 PM','FAIL');
insert into syntrans values (  1, '19-APR-17 07.34.08.567579 PM','SUCCESS');
insert into syntrans values (  1, '19-APR-17 08.07.31.731745 PM','SUCCESS');
insert into syntrans values (  1, '19-APR-17 08.07.32.735582 PM','SUCCESS');
insert into syntrans values (  2, '19-APR-17 08.17.51.332804 PM','FAIL');
insert into syntrans values (  2, '19-APR-17 08.17.52.336530 PM','FAIL');
insert into syntrans values (  2, '19-APR-17 08.19.27.993327 PM','SUCCESS');
insert into syntrans values (  2, '19-APR-17 08.25.54.860077 PM','FAIL');
insert into syntrans values (  2, '19-APR-17 08.25.55.862830 PM','SUCCESS');

我目前得到的是

SELECT transid,
       launchtime,
       status,
       rank() over (partition by status order by launchtime) rnk
  FROM syntrans 
 order by transid, launchtime, status;

   TRANSID LAUNCHTIME                     STATUS            RNK
---------- ------------------------------ ---------- ----------
         1 19-APR-17 07.34.05.824875 PM   FAIL                1
         1 19-APR-17 07.34.06.828753 PM   FAIL                2
         1 19-APR-17 07.34.08.567579 PM   SUCCESS             1
         1 19-APR-17 08.07.31.731745 PM   SUCCESS             2
         1 19-APR-17 08.07.32.735582 PM   SUCCESS             3
         2 19-APR-17 08.17.51.332804 PM   FAIL                3
         2 19-APR-17 08.17.52.336530 PM   FAIL                4
         2 19-APR-17 08.19.27.993327 PM   SUCCESS             4
         2 19-APR-17 08.25.54.860077 PM   FAIL                5
         2 19-APR-17 08.25.55.862830 PM   SUCCESS             5

需要的输出是这样的:

   TRANSID LAUNCHTIME                     STATUS            RNK
---------- ------------------------------ ---------- ----------
         1 19-APR-17 07.34.05.824875 PM   FAIL                1
         1 19-APR-17 07.34.06.828753 PM   FAIL                2
         1 19-APR-17 07.34.08.567579 PM   SUCCESS             1
         1 19-APR-17 08.07.31.731745 PM   SUCCESS             2
         1 19-APR-17 08.07.32.735582 PM   SUCCESS             3
         2 19-APR-17 08.17.51.332804 PM   FAIL                1
         2 19-APR-17 08.17.52.336530 PM   FAIL                2
         2 19-APR-17 08.19.27.993327 PM   SUCCESS             1
         2 19-APR-17 08.25.54.860077 PM   FAIL                1
         2 19-APR-17 08.25.55.862830 PM   SUCCESS             1

...每次状态值改变时("按日期排序"),"等级"开始.我知道我得到的输出是按整体状态组排名,但我无法找到任何功能组合来获得所需的输出.

这几乎得到了它,但并不完全:

SELECT transid, launchtime, status, rnk
  FROM (SELECT transid,
              status,
              launchtime,
              RANK() OVER (PARTITION BY transid, status ORDER BY launchtime) rnk
         FROM syntrans )
ORDER BY transid, launchtime;

Answer 1

您可以使用行号差异方法将连续的相同状态行分类为一组。（运行内部查询以查看如何分配组。）然后row_number与这些组一起使用。

SELECT transid, launchtime, status
,ROW_NUMBER() over(PARTITION BY transid,grp ORDER BY launchtime) as rnk
FROM (SELECT  transid,
              status,
              launchtime,
              ROW_NUMBER() OVER (PARTITION BY transid ORDER BY launchtime)
              -ROW_NUMBER() OVER (PARTITION BY transid, status ORDER BY launchtime) as grp
         FROM syntrans) t