PostgreSQL:使用语言 plpgsql 从函数返回 JSON

MAK*_*MAK 5 postgresql plpgsql

我有下表,其中包含两个字段:

create table tbl_jtest
(
cola int,
colb varchar(10)
);
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插入一些记录:

insert into tbl_jtest values(1,'a');
insert into tbl_jtest values(2,'b');
insert into tbl_jtest values(3,'c');
insert into tbl_jtest values(4,'d');
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功能

CREATE OR REPLACE FUNCTION ufn_jtest1(pcola int) 
RETURNS json AS
$$
BEGIN
IF pcola = 1 
THEN
    RETURN QUERY SELECT to_json(a.cola) FROM tbl_jtest a;
ELSE
    RETURN QUERY  SELECT to_json(a.colb) FROM tbl_jtest a;
END IF;
END;
$$ LANGUAGE plpgsql;
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错误详情

错误:不能在非 SETOF 函数中使用 RETURN QUERY 第 7 行:RETURN QUERY SELECT to_json(a.cola) FROM tbl_jtest a; ^

我尝试了以下方法:

尝试 1

PERFORM to_json(a.cola) FROM tbl_jtest a;
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尝试 2

RETURN QUERY PERFORM to_json(a.cola) FROM tbl_jtest a;
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ets*_*tsa 5

或者你正在寻找这样的东西?

create table tbl_jtest
(
cola int,
colb varchar(10),
colc varchar(10)

);

insert into tbl_jtest values(1,'a','e');
insert into tbl_jtest values(2,'b','f');
insert into tbl_jtest values(3,'c','g');
insert into tbl_jtest values(4,'d','h');


SELECT * FROM tbl_jtest;

CREATE OR REPLACE FUNCTION ufn_jtest1(pcola int) 
RETURNS table (j json) AS
$$
BEGIN
IF pcola = 1 
THEN
    RETURN QUERY  SELECT row_to_json(a) FROM (SELECT cola, colb FROM tbl_jtest) a;
ELSE
    RETURN QUERY  SELECT to_json(a) FROM (SELECT colb, colc FROM tbl_jtest) a;
END IF;
END;
$$ LANGUAGE plpgsql;
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测试 1

SELECT ufn_jtest1(1);
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输出 1

    ufn_jtest1
1   {"cola":1,"colb":"a"}
2   {"cola":2,"colb":"b"}
3   {"cola":3,"colb":"c"}
4   {"cola":4,"colb":"d"}
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测试2

SELECT ufn_jtest1(2);
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输出 2 ufn_jtest1

1   {"colb":"a","colc":"e"}
2   {"colb":"b","colc":"f"}
3   {"colb":"c","colc":"g"}
4   {"colb":"d","colc":"h"}
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