将大量可观察量聚合为新的可观察量

Question

比方说,我有1000个观察者.现在我想将所有事件聚合到一个新的observable中,一旦所有其他事件发送了一个事件,它就会触发OnNext.什么是使用Rx做到这一点的最佳方法？

更新:在Rx论坛上有一些很棒的反馈,尤其是Dave Sexton.他展示了如何创建一个带有多个observable的Zip扩展方法:http://social.msdn.microsoft.com/Forums/en-US/rx/thread/daaa84db-b560-4eda-871e-e523098db20c/

Answer 1

F# 中有一个 MailboxProcessor...我会在 C# 中使用 SynchronizationContext 来达到相同的目的。给我几分钟，我会写一个例子。

旁白：这是我在 F# 中的代码，它执行类似的操作...这将花费更多的精力，但在带有 Rx 的 C# 中仍然可行。

open System.Diagnostics

let numWorkers = 20
let asyncDelay = 100

type MessageForMailbox =
   | DataMessage of AsyncReplyChannel<unit>
   | GetSummary of AsyncReplyChannel<unit>

let main =
   let actor =
      MailboxProcessor.Start( fun inbox ->
         let rec loop acc =
            async {
               let! message = inbox.Receive()
               match message with
               | DataMessage replyChannel -> replyChannel.Reply(); return! loop acc
               | GetSummary replyChannel -> replyChannel.Reply(); return! loop acc
            }

         loop 0 // seed for acc
      )

   let codeBlocks = [for i in 1..numWorkers -> 
                        async {
                           do! Async.Sleep asyncDelay
                           return! actor.PostAndAsyncReply DataMessage
                        } ]

   while true do
      printfn "Concurrent started..."
      let sw = new Stopwatch()
      sw.Start()
      codeBlocks |> Async.Parallel |> Async.RunSynchronously |> ignore
      actor.PostAndReply GetSummary
      sw.Stop()
      printfn "Concurrent in %d millisec" sw.ElapsedMilliseconds
      printfn "efficiency: %d%%" (int64 (asyncDelay * 100) / sw.ElapsedMilliseconds)

      printfn "Synchronous started..."
      let sw = new Stopwatch()
      sw.Start()
      for codeBlock in codeBlocks do codeBlock |> Async.RunSynchronously |> ignore
      sw.Stop()
      printfn "Synchronous in %d millisec" sw.ElapsedMilliseconds
      printfn "efficiency: %d%%" (int64 (asyncDelay * numWorkers * 100) / sw.ElapsedMilliseconds)

main