通过使用SQL将它们映射到新行,将逗号分隔为两列的值

Question

ID        NAME          COMMENTS
1          ABC           HI
2,3        DEF,GHI       HELLO
4          JKL           HII
5,6,7      M,N,O         HEY

我在上面提到的数据中使用逗号分隔值,这些逗号分隔值按顺序映射.对于Eg.id 1与ABC相关,2与DEF相关,3与GHI相关,依此类推.

我想使用sql查询来获得以下输出:

ID        NAME      COMMENTS
1          ABC        HI
2          DEF        HELLO
3          GHI        HELLO
4          JKL        HII
5          M          HEY
6          N          HEY
7          O          HEY

Answer 1

在SQL Server 2016+中,您可以使用string_split().

在SQL Server 2016之前,您需要一些其他方法来拆分字符串.使用Jeff Moden的CSV Splitter表值函数:

select 
    id = i.item
  , name = n.item
  , comments = t.comments
from t
  cross apply dbo.delimitedsplit8k(t.id,',') i
  cross apply dbo.delimitedsplit8k(t.name,',') n
where i.itemnumber = n.itemnumber

rextester 演示:http://rextester.com/EEFRS3810

收益:

+----+------+----------+
| id | name | comments |
+----+------+----------+
|  1 | ABC  | HI       |
|  2 | DEF  | HELLO    |
|  3 | GHI  | HELLO    |
|  4 | JKL  | HII      |
|  5 | M    | HEY      |
|  6 | N    | HEY      |
|  7 | O    | HEY      |
+----+------+----------+

拆分字符串参考:

• Tally OH!改进的SQL 8K"CSV分离器"功能 - Jeff Moden
• 分裂字符串:后续行动 - Aaron Bertrand
• 以正确的方式分割弦乐 - 或者是下一个最好的方式 - Aaron Bertrand
• string_split() 在SQL Server 2016中:后续#1 - Aaron Bertrand

使用John Cappelletti的内联xml字符串拆分器:

select 
    id = i.RetVal
  , name = n.RetVal
  , comments = t.comments
from t
   Cross Apply (
                Select RetSeq = Row_Number() over (Order By (Select null))
                      ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                From  (Select x = Cast('<x>' + replace((Select replace(t.[Id],',','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as x
                Cross Apply x.nodes('x') AS B(i)
             ) i
   Cross Apply (
                Select RetSeq = Row_Number() over (Order By (Select null))
                      ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                From  (Select x = Cast('<x>' + replace((Select replace(t.[Name],',','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as x
                Cross Apply x.nodes('x') AS B(i)
             ) n
where i.RetSeq = n.RetSeq

rextester演示:http://rextester.com/ZCKVNV72753