异步和等待C#和问题

Question

此程序不会以正确的顺序打印输出.

public static void Main(string[] args)
    {
        new Program().Start();
    }

    public async void Start()
    {
        int num1 = await GetNumber();
        int num2 = await GetNumber();
        int num3 = await GetNumber();
        Console.WriteLine("Wait...");
        Console.ReadKey();
    }

    public static async Task<int> GetNumber()
    {
        System.Threading.Thread.Sleep(4000);
        Console.WriteLine("Hello");
        return 0;
    }

它输出:

--------wait 4Seconds
--------print Hello
--------wait 4Seconds
--------print Hello
--------wait 4Seconds
--------print Hello
--------print wait....

它应该输出

--------print wait....
--------wait 4Seconds
--------print Hello
--------print Hello
--------print Hello

Answer 1

使用

Await Task.Delay(Timespan.FromMilliSeconds (4000))

而不是Thread.Sleep.

完全成功的例子.

using System;
using System.Threading.Tasks;

namespace Brad
{
    public class Program
    {
        public static void Main(string[] args)
        {
            var task = new Program().Start();
            Console.WriteLine("Wait...");
            // You have to put a synchronous Wait() here because
            // Main cannot be declared as async
            task.Wait();
        }

        public async Task Start()
        {
            int num1 = await GetNumber();
            int num2 = await GetNumber();
            int num3 = await GetNumber();
            Console.WriteLine("Finished");
        }

        public static async Task<int> GetNumber()
        {
            await Task.Delay(TimeSpan.FromMilliseconds(400));
            Console.WriteLine("Hello");
            return 0;
        }
    }
}

你可以看到它在这里运行

https://dotnetfiddle.net/KHJaDZ

或者您可能希望并行运行任务而不是一个接一个地运行.你可以试试

using System;
using System.Threading.Tasks;

namespace Brad
{
    public class Program
    {
        public static void Main(string[] args)
        {
            var task = new Program().Start();
            Console.WriteLine("Wait...");
            // You have to put a synchronous Wait() here because
            // Main cannot be declared as async
            task.Wait();
        }

        public async Task Start()
        {
            var task1 = GetNumber();
            var task2 = GetNumber();
            var task3 = GetNumber();
            // This runs the tasks in parallel
            await Task.WhenAll(task1, task2, task3);
            Console.WriteLine("Finished");
        }

        public static async Task<int> GetNumber()
        {
            await Task.Delay(TimeSpan.FromMilliseconds(400));
            Console.WriteLine("Hello");
            return 0;
        }
    }
}

这是在这里运行.

https://dotnetfiddle.net/kVk77Z