Mysql:按值频率排序行

Question

假设我有这张表:

+----+------+---------+
| Id | Item | Country |
+----+------+---------+
|  1 | b123 | Austria |
|  2 | a123 | Italy   |
|  3 | b990 | Germany |
|  4 | h231 | Austria |
|  5 | y233 | France  |
|  6 | u223 | Austria |
|  7 | p022 | Spain   |
|  8 | d133 | Italy   |
|  9 | w112 | Germany |
| 10 | j991 | Austria |
+----+------+---------+

我想SELECT在那张桌子上做一个并按顺序排列Country最重复的结果.所以预期的输出应该是:

+----+------+---------+
| Id | Item | Country |
+----+------+---------+
|  1 | b123 | Austria |
|  4 | h231 | Austria |
|  6 | u223 | Austria |
| 10 | j991 | Austria |
|  2 | a123 | Italy   |
|  8 | d133 | Italy   |
|  3 | b990 | Germany |
|  9 | w112 | Germany |
|  5 | y233 | France  |
|  7 | p022 | Spain   |
+----+------+---------+

我怎样才能做到这一点？

我试过这个:

SELECT * FROM items WHERE Item != '' GROUP BY Item HAVING COUNT(*) > 1 ORDER BY COUNT(*) DESC

但这会返回这样的东西:

+----+------+---------+
| Id | Item | Country |
+----+------+---------+
|  1 | b123 | Austria |
|  8 | d133 | Italy   |
|  3 | b990 | Germany |
|  5 | y233 | France  |
|  7 | p022 | Spain   |
+----+------+---------+

Answer 1

A - Original table
B - Getting the counts at Country Level.

通过连接A和B,我们可以按计数的降序对数据进行排序,并显示表中的所有项目.

SELECT A.*
  FROM items A
INNER JOIN 
(    SELECT Country,COUNT(*) AS cnt       
      FROM items 
     WHERE Item != '' 
     GROUP BY Item 
) B
   ON A.Country = B.Country
ORDER BY B.cnt DESC,A.Country,A.Id;