loc*_*e14 6 c++ opencv image-processing mat opencv-mat
我想使用分配给其他位置的数据(每个通道的像素在一起)来创建OpenCV 3通道Mat,这不同于OpenCV Mat的数据,其中来自不同通道的数据是交错的。
Mat outputMat = Mat(dimY, dimX, CV_8UC3, rawData);
// This works only if rawData interleaves channel data like an OpenCv Mat
Run Code Online (Sandbox Code Playgroud)
有没有一种方法可以创建OpenCV Mat,而不必采用以下从临时Mat分割通道并将正确的通道数据复制到相应位置的解决方案?
void createMat(unsigned char *rawData, unsigned int dimX, unsigned int dimY)
{
Mat outputMat = Mat(dimY, dimX, CV_8UC3);
// use outputMat to draw some stuff
Mat channelR = Mat(dimY, dimX, CV_8UC1, rawData);
Mat channelG = Mat(dimY, dimX, CV_8UC1, rawData + dimX * dimY);
Mat channelB = Mat(dimY, dimX, CV_8UC1, rawData + 2 * dimX * dimY);
std::vector<Mat> channels(3);
split(outputMat, channels);
channels[2].copyTo(channelR);
channels[1].copyTo(channelG);
channels[0].copyTo(channelB);
}
Run Code Online (Sandbox Code Playgroud)
我需要经常执行此操作,因此我想知道是否有一种解决方案不涉及每次都调用split()
and copyTo()
函数。
谢谢!
您可以避免split
和直接copyTo
使用merge
。
Mat createMat(unsigned char *rawData, unsigned int dimX, unsigned int dimY)
{
// No need to allocate outputMat here
Mat outputMat;
// Build headers on your raw data
Mat channelR(dimY, dimX, CV_8UC1, rawData);
Mat channelG(dimY, dimX, CV_8UC1, rawData + dimX * dimY);
Mat channelB(dimY, dimX, CV_8UC1, rawData + 2 * dimX * dimY);
// Invert channels,
// don't copy data, just the matrix headers
std::vector<Mat> channels{ channelB, channelG, channelR };
// Create the output matrix
merge(channels, outputMat);
return outputMat;
}
Run Code Online (Sandbox Code Playgroud)
我测试了其他一些方法,但它们的速度较慢。只是为了记录,我认为这会更快,但转置真的很重:
Mat outputMat(3, dimY*dimX, CV_8UC1, rawData);
Mat tmp = outputMat.t();
outputMat = tmp.reshape(3, dimY);
cvtColor(outputMat, outputMat, COLOR_RGB2BGR);
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
4788 次 |
最近记录: |