我需要将工作日名称解析为DayOfWeek
. 星期名称可以是短('Mon')或长('Monday')格式。
目前我想出了这样的解决方案:
DateTimeFormatter dtf = DateTimeFormatter.ofPattern("EEE", locale);
DayOfWeek dayOfWeek;
try {
dayOfWeek = DayOfWeek.from(dtf.parse(value));
}
catch (DateTimeException e) {
dtf = DateTimeFormatter.ofPattern("EEEE", locale);
dayOfWeek = DayOfWeek.from(dtf.parse(value));
}
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有更短的解决方案吗?
您可以使用DateTimeFormatterBuilder
可选模式。这些将按照您附加它们的顺序进行尝试。DateTimeException
如果所有模式都失败,仍然会抛出A。
final DateTimeFormatter dtf = new DateTimeFormatterBuilder()
.appendOptional(DateTimeFormatter.ofPattern("EEEE"))
.appendOptional(DateTimeFormatter.ofPattern("E"))
.toFormatter(locale);
final DayOfWeek dow1 = DayOfWeek.from(dtf.parse("Mon"));
final DayOfWeek dow2 = DayOfWeek.from(dtf.parse("Monday"));
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请注意,DayOfWeek
如果您愿意,结果现在可以是最终的。
尝试跨多种语言(多个区域设置)使用相同的代码。
for ( final Locale locale : new Locale[] { Locale.US , Locale.CANADA_FRENCH , Locale.ITALY , Locale.KOREA } ) {
final String inputShort = ( DayOfWeek.MONDAY.getDisplayName ( TextStyle.SHORT, locale ) );
final String inputFull = ( DayOfWeek.MONDAY.getDisplayName ( TextStyle.FULL, locale ) );
final DateTimeFormatter dtf = new DateTimeFormatterBuilder ( )
.appendOptional ( DateTimeFormatter.ofPattern ( "EEEE" ) )
.appendOptional ( DateTimeFormatter.ofPattern ( "E" ) )
.toFormatter ( locale );
final DayOfWeek dow1 = DayOfWeek.from ( dtf.parse ( inputShort ) );
final DayOfWeek dow2 = DayOfWeek.from ( dtf.parse ( inputFull ) );
System.out.println ( "" );
System.out.println ( "Language: " + locale.getDisplayLanguage ( Locale.US ) );
System.out.println ( "inputShort: " + inputShort + " | dow1: " + dow1 );
System.out.println ( "inputFull: " + inputFull + " | dow2: " + dow2 );
}
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跑的时候。
final DateTimeFormatter dtf = new DateTimeFormatterBuilder()
.appendOptional(DateTimeFormatter.ofPattern("EEEE"))
.appendOptional(DateTimeFormatter.ofPattern("E"))
.toFormatter(locale);
final DayOfWeek dow1 = DayOfWeek.from(dtf.parse("Mon"));
final DayOfWeek dow2 = DayOfWeek.from(dtf.parse("Monday"));
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