ygl*_*odt 0 sql postgresql gaps-and-islands
请考虑下表:
create table measurement (
datetime timestamp,
temperature numeric(5,2)
);
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我想创建一个SQL-query,PostgreSQL其中提取温度高于50°C的行至少30分钟,理想情况下从何时知道温度实际高于50°C.示例数据如下:
datetime temperature
------------------- -----------
2017-03-15 19:00:10 49.56
2017-03-15 19:15:10 52.81
2017-03-15 19:30:10 49.00
2017-03-15 19:45:10 52.88
2017-03-15 20:00:10 49.56
2017-03-15 20:15:10 49.13
2017-03-15 20:30:10 51.31 <--
2017-03-15 20:45:10 52.06 <--
2017-03-15 21:00:10 50.50 <--
2017-03-15 21:15:10 50.50 <--
2017-03-15 21:30:10 49.38
2017-03-15 21:45:10 47.44
2017-03-15 22:00:10 46.19
2017-03-15 22:15:10 45.44
2017-03-15 22:30:10 50.25
2017-03-15 22:45:10 48.56
2017-03-15 23:00:10 51.25 <--
2017-03-15 23:15:10 50.44 <--
2017-03-15 23:30:10 50.63 <--
2017-03-15 23:45:10 46.75
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因此,温度高于50的第一个身份组.这是一个缺口和岛屿问题.然后,您可以汇总岛屿以获取您想要的信息:
select min(datetime), max(datetime), count(*) as numrecs, avg(temperature)
from (select t.*,
row_number() over (order by datetime) as seqnum,
row_number() over (partition by (temperature >= 50)::int
order by datetime) as seqnum_t
from t
) t
where temperature >= 50
group by (seqnum - seqnum_t)
having max(datetime) >= min(datetime) + interval '30' minute;
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