Java 8显示了此错误.在封闭范围内定义的局部变量itemList必须是最终的或有效的最终

Nav*_*run 2 java java-8 java-stream

我正在使用java 8编写代码,但我迭代a List然后RestaurantOrderBook使用类别类型查找.把它List放进去Map.它显示了这个错误:

在封闭范围内定义的局部变量itemList必须是最终的或有效的最终

Query query = new Query();
String categ = category;
query.addCriteria(Criteria.where("restaurantId").is(restaurantId));

List<RestaurantOrderBook> itemList = new ArrayList<RestaurantOrderBook>();
itemList = mongoTemplate.find(query, RestaurantOrderBook.class);
System.out.println("size : " + itemList.size());
Map<String , List<RestaurantOrderBook>> map = new HashMap<String , List<RestaurantOrderBook>>();
        Arrays.asList("TakeAway", "Dining").forEach(e ->{

//Following line throws error:              
List<RestaurantOrderBook> list  = itemList.stream().filter(a -> !a.getOrderType().isEmpty() && a.getOrderType().equals(e)).collect(Collectors.toList());
                map.put(e, list);
        });
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我有另一种情况:

@Override
    public EventReportRewardsPoints eventReportRewardsPoints(String organizerId) {
        try{
            List<Event> listOfEvents = eventRepo.findByOrganizerId(organizerId);
            EventReportRewardsPoints eventTransReport = new EventReportRewardsPoints();
            Integer soldTics = 0;
            Double totalRevenue = 0d;
            Integer soldToday  = 0;

            Integer findTotalAvailableTics = 0;
            Integer findTotalQtytics = 0;

            for (Event event : listOfEvents) {
                List<EventTicket> eventTicket = eventTicketRepo.findByEventId(event.getId());

                Integer sumOfAvailabletics = eventTicket.stream()
                        .mapToInt(EventTicket::getRemainingTickets).sum();
                findTotalAvailableTics = findTotalAvailableTics + sumOfAvailabletics;

                Integer sumOfQtytics = eventTicket.stream().mapToInt(EventTicket::getQty).sum();
                findTotalQtytics  = findTotalQtytics + sumOfQtytics;

                List<EventTicketBook> listOfEventsTic = eventTicketBookRepository.findByEventId(event.getId());
                for (EventTicketBook eventTicketBook : listOfEventsTic) {
                    Double sumOfSales = eventTicketBook.getTickets().stream().mapToDouble(EventTicket::getPrice).sum();
                    totalRevenue = totalRevenue + sumOfSales;
                    Date now = new Date();
                    System.out.println("create date : " + eventTicketBook.getCreateOn());
                    /*if(now.compareTo(eventTicketBook.getCreateOn()) == 0){
                        Integer sumOfSoldToday = eventTicketBook.getTickets().stream().mapToInt(EventTicket::getQty).sum();
                        soldToday = soldToday + sumOfSoldToday;
                    }*/
                }
            }
            System.out.println("findTotalQtytics : " + findTotalQtytics);
            System.out.println("findTotalAvailableTics : " + findTotalAvailableTics);
            soldTics = findTotalQtytics - findTotalAvailableTics;
            eventTransReport.setTotalRevenue(totalRevenue);
            eventTransReport.setSoldToday(soldToday);
            eventTransReport.setTicketsSold(soldTics);
            return eventTransReport;
        }catch(Exception e ){
            e.printStackTrace();
        }
        return null;
    }
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我如何使用lamda表达式实现此目的.

wum*_*mpz 7

您正在lambda表达式中使用itemList.因此它必须是最终的.

Java 8引入了有效final的新概念,这意味着,如果使用的变量是最终使用的,并且不强制开发人员明确地将其声明为final,则编译器会检查.

因此,如果您将代码更改为

final List<RestaurantOrderBook> itemList = new ArrayList<RestaurantOrderBook>();
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你会看到编译器给你一个错误:

itemList = mongoTemplate.find(query, RestaurantOrderBook.class);
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因为你正在重新分配itemList.这就是为什么itemList也没有有效的最终结果.如果你压扁这两行

List<RestaurantOrderBook> itemList = mongoTemplate.find(query, RestaurantOrderBook.class);
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它应该工作.

  • 是.final只表示,您不能将itemList设置为另一个List实例,但这并不意味着您的List实例本身是只读的. (2认同)