如何在for循环和switch-case中生成100个不同的引用变量？

Question

我想基于Position枚举类型创建100个新实例.在switch case语句中我有5个案例,并且基于enum类型我想创建相应的Employee实例.我的问题是,我不知道如何在每次创建新实例时创建和分配新的变量名,例如:worker1,worker2,worker3.这是我到目前为止所得到的:

final String randomVariableName() {
        int count = 1;
        String s = "worker" + count;
        count++;
        return s;
    }

final Position randomPosition(){
    return positions[random.nextInt(positions.length)];
}
public void run() {
    for (int i = 1; i <= 100; i++) {
        String randomName = "worker" + i;
        Position p = randomPosition();
        switch (p) {
            case PROJECT_LEADER:
                ProjectLeader randomVariableName() = new ProjectLeader(p, randomName, 5000);
            case DEVELOPER_LEADER:
                DeveloperLeader randomVariableName() = new DeveloperLeader(p, randomName, 1000);
        }
    }

但是这样,我无法调用该randomVariableName()方法,因为:Variable 'randomVariableName' is already defined in the scope

我甚至不确定,这将是一个很好的解决方案.我只需要一种方法,在switch-case中创建100个唯一的引用变量名.

Answer 1

您无法在Java中在运行时创建新的变量名称.您可以做的是使用数组或集合来存储实例.

Employee employees[] = new Employee employees[100];

for (int i = 0; i < 100; i++) {
        String randomName = "worker" + i;
        Position p = randomPosition();
        switch (p) {
            case PROJECT_LEADER:
                employees[i] = new ProjectLeader(p, randomName, 5000);
                break;
            case DEVELOPER_LEADER:
                employees[i] = new DeveloperLeader(p, randomName, 1000);
                break;
        }
    }

在循环后,您可以访问employees[0]通过employees[99]让你的100个实例.

甚至比使用原始数组更合适的是集合,例如ArrayList<Employee>您添加实例的集合.

另外 - 记得在switch()内部中断你的case语句