按数字顺序对"高级"数字字符串进行排序

Question

想象一下这个数组:

var fees = [
    '$0.9 + $0.1',
    '$20 + $2',
    '$0.7 + $0.4',
    '$5 + $0.5',
    '$0 + $0.01',
    '$100 + $9',
    '$1 + $1',
    '$2 + $0.5'
];

如果使用vanilla JavaScript,我将如何按数字升序排序这些字符串值？

排序后所需的输出:

['$0 + $0.01', '$0.7 + $0.4', '$0.9 + $0.1', '$1 + $1', '$2 + $0.5', '$5 + $0.5', '$20 + $2', '$100 + $9']

我尝试了以下方法:

function mySort(a, b) {
    return ((a < b) ? -1 : ((a > b) ? 1 : 0));
}

但这只是输出:

["$0 + $0.01", "$0.7 + $0.4", "$0.9 + $.1", "$1 + $1", "$100 + $9", "$2 + $0.5", "$20 + $2", "$5 + $0.5"]`

这可能是一个整洁和合乎逻辑的方式吗？

我不希望得到这笔钱,因为它会产生不必要的结果.考虑的例子"$0.9 + $0.1"和"$0.7 + $0.4"."$0.9 + $0.1"将是一个较低的值,因为总和是1,但我想排序,所以这"$0.7 + $0.4"是一个较低的值而不是.所以基本上希望对第一个数字进行排序,如果第一个数字在两个值之间相同,那么对第二个数字进行排序

Answer 1

根据字符串中的数字总和进行排序.

var fees = ['$0.9 + $.1', '$20 + $2', '$5 + $0.5', '$0 + $0.01', '$100 + $9', '$1 + $1', '$2 + $0.5'];

fees.sort(function(a, b) {
  return getSum(a) - getSum(b);
})

function getSum(str) {
  return str
    // remove the $ and space
    .replace(/[^\d+.]/g, '')
    //split by + symbol
    .split('+')
    // get the sum
    .reduce(function(sum, s) {
      // parse and add with sum
      return sum + (Number(s) || 0);
      // set inital value as sum
    }, 0)
}

console.log(fees);

您可以使用保存总和的其他对象来加快进程.

var fees = ['$0.9 + $.1', '$20 + $2', '$5 + $0.5', '$0 + $0.01', '$100 + $9', '$1 + $1', '$2 + $0.5'];

var ref = fees.reduce(function(obj, str) {
  // define object property if not defined
  obj[str] = str in obj || str
    // remove the $ and space
    .replace(/[^\d+.]/g, '')
    //split by + symbol
    .split('+')
    // get the sum
    .reduce(function(sum, s) {
      // parse and add with sum
      return sum + (Number(s) || 0);
      // set inital value as sum
    }, 0);
  // return the object reference
  return obj;
  // set initial value as an empty objecct
}, {})

fees.sort(function(a, b) {
  return ref[a] - ref[b];
})



console.log(fees);

更新:由于您已更新问题,因此需要比较各个部分.

var fees = ['$0.9 + $.1', '$20 + $2', '$5 + $0.5', '$0 + $0.01', '$100 + $9', '$1 + $1', '$2 + $0.5'];

fees.sort(function(a, b) {
  // get numbers from a
  var arrA = a.replace(/[^\d.+]/g, '').split('+');
  // get numbers from b
  var arrB = b.replace(/[^\d.+]/g, '').split('+');

  // generate sort value
  return arrA[0] - arrB[0] || arrA[1] - arrB[1];
})

console.log(fees);