我已经调用了Api并使用RestSharp接收了此响应.我无法控制Json响应的结构.
{
"response": {
"result": {
"Leads": {
"row": [
{
"no": "1",
"FL": [
{
"val": "LEADID",
"content": "101"
},
{
"val": "Company",
"content": "Test 1"
}
]
},
{
"no": "2",
"FL": [
{
"val": "LEADID",
"content": "102"
},
{
"val": "Company",
"content": "Test 2"
}
]
}
]
}
},
"uri": "/crm/private/json/Leads/getRecords"
}
}
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我想在理想情况下从Json中提取一个Leads列表作为Dto,而不进行可怕的解析等.
所以例如我会创建一个Dto类:
public class LeadDto {
public string LeadId;
public string Company;
}
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这些潜在客户可以包含在列表或其他内容中.
我已经阅读了https://github.com/restsharp/RestSharp/wiki/Deserialization多年但没有到达任何地方.
任何人都能用实例指出我正确的方向吗?
Cod*_*shi 13
复制JSON,然后在Visual Studio中,在菜单栏中转到:编辑>选择性粘贴>将JSON粘贴为类:
它将为您的JSON生成以下内容:
public class Rootobject {
public Response response { get; set; }
}
public class Response {
public Result result { get; set; }
public string uri { get; set; }
}
public class Result {
public Leads Leads { get; set; }
}
public class Leads {
public Row[] row { get; set; }
}
public class Row {
public string no { get; set; }
public FL[] FL { get; set; }
}
public class FL {
public string val { get; set; }
public string content { get; set; }
}
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您也可以通过选择"将XML粘贴为类"选项对XML执行相同操作.
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