如何捕获pg_connect()函数错误？

Question

pg_connect()以表格格式显示错误.而不是显示错误消息,因为表格格式需要错误消息警报.

错误消息
警告:pg_connect()[function.pg-connect]:无法连接到PostgreSQL服务器:致命错误:第41行/home/test/public_html/QueueManager/Modules/Database.php中的用户"test"密码验证失败

如果以表格格式显示错误.
执行pg_connect()后抛出异常.
但是不行.

码

function connect()
{
  $HOST = $GLOBALS[Database_Conn][Db_Host];     # Host name 
  $USER = $GLOBALS[Database_Conn][Db_User];     # database user name 
  $DBNAME = $GLOBALS[Database_Conn][Db_Name];   # name of the database
  $PASSWORD = $GLOBALS[Database_Conn][Db_Pass]; # password the database user.

  try 
  {
    $conn = pg_connect("host=$HOST dbname=$DBNAME user=$USER ".
                       "password=$PASSWORD sslmode=disable");
    if(!$conn)
    {
      throw new Exception("Database Connection Error");
    }
    return $conn;
  }
  catch (Exception $e) 
  {
    print <<<_HTML_
    <script> alert('Caught exception'); 
    </script> _HTML_;
    die();
  }
}

请给我解决方案

Answer 1

pg_connect 不抛出异常,所以你必须转换为异常,如下所示.

function exception_error_handler($errno, $errstr, $errfile, $errline ) {
    throw new ErrorException($errstr, $errno, 0, $errfile, $errline);
}
set_error_handler("exception_error_handler");

try {
    $conn=@pg_connect("host=dbhost user=dbuser dbname=db password=dbpass");
} Catch (Exception $e) {
    Echo $e->getMessage();
}

请参考这个更多细节

http://php.net/manual/en/language.exceptions.php

Answer 2

要隐藏 PHP 生成的错误文本，请在函数调用前添加 @，例如：

$conn = @pg_connect("host=$HOST dbname=$DBNAME user=$USER ".
                   "password=$PASSWORD sslmode=disable");

更多细节在这里