ap2*_*p21 5 python plot plotly
我有一个Plotly Scatter3d()图,我想在其中一些之间画线。从物理上讲,我有一个网络,其中有一些节点通过键连接,我想绘制这些键。我该怎么办?
Scatter3d()带有一个mode='lines+markers'仅使它成为点和线散点图的选项,而不是默认的仅点图。那不是我想要的。我想提供一个xyz坐标对列表,并且我想在末尾收集行。
这是我绘制简单Scatter3d()图的功能:
def Splot3dPlotly(xyz):
'''
3D scatter plot using Plotly.
:param xyz: (NPx3) array of xyz positions
:return: A Plotly figure that can now be plotted as usual.
'''
xyz = np.reshape(xyz, (int(xyz.size/3), 3))
NN = int(sqrt(xyz.shape[0]))
trace1 = go.Scatter3d(
x=xyz[:,0],
y=xyz[:,1],
z=xyz[:,2],
mode = 'markers', # 'lines+markers',
marker=dict(color=range(NN*NN), colorscale='Portland')
)
data = [trace1]
layout = go.Layout(
margin=dict(
l=0,
r=0,
b=0,
t=0
)
)
fig = go.Figure(data=data, layout=layout)
return fig
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Max*_*ers 12
您可以使用线条添加第二条轨迹,并且每个坐标对都由 分隔,None以防止 Plotly 连接轨迹。
import plotly.graph_objs as go
import plotly
plotly.offline.init_notebook_mode()
#draw a square
x = [0, 1, 0, 1, 0, 1, 0, 1]
y = [0, 1, 1, 0, 0, 1, 1, 0]
z = [0, 0, 0, 0, 1, 1, 1, 1]
#the start and end point for each line
pairs = [(0,6), (1,7)]
trace1 = go.Scatter3d(
x=x,
y=y,
z=z,
mode='markers',
name='markers'
)
x_lines = list()
y_lines = list()
z_lines = list()
#create the coordinate list for the lines
for p in pairs:
for i in range(2):
x_lines.append(x[p[i]])
y_lines.append(y[p[i]])
z_lines.append(z[p[i]])
x_lines.append(None)
y_lines.append(None)
z_lines.append(None)
trace2 = go.Scatter3d(
x=x_lines,
y=y_lines,
z=z_lines,
mode='lines',
name='lines'
)
fig = go.Figure(data=[trace1, trace2])
plotly.offline.iplot(fig, filename='simple-3d-scatter')
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