Suh*_*pta 0 javascript static typescript
在一个类中,有几种static方法,要调用的方法将在运行时确定。如何动态调用此方法?
export default class channel {
// METHOD THAT WILL DYNAMICALLY CALL OTHER STATIC METHODS
private static methodMap = {
'channel-create' : 'create',
'channel-user-count' : 'userCount',
'channel-close' : 'close'
};
public static do(commandType:string,params: any) {
if(channel.methodMap.hasOwnProperty(commandType)) {
// GET NAME OF THE METHOD
let method = channel.methodMap[commandType];
// CALL METHOD ON THE FLY
//return channel.call(method,params);
// channel.userCount(params);
}
}
/**
* Adds channel to available channel list
*/
private static create(channelName:string) {
}
/**
* Returns count of users in the channel
*/
private static userCount(channelName:string) {
}
}
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您可以使用来动态调用方法Classname['methodName'](param)。与您的情况一样,您可以将create方法调用为Channel['create']('MyChannel')
这是工作示例:Typescript Playground
class Channel {
private static methodMap = {
'channel-create' : 'create',
'channel-user-count' : 'userCount',
'channel-close' : 'close'
};
private static create(channelName:string) {
alert('Called with ' + channelName);
}
private static userCount(channelName:string) {
alert('Usercount called with ' + channelName);
}
public static do(commandType: string, params: any) {
if(Channel.methodMap.hasOwnProperty(commandType)) {
let method = Channel.methodMap[commandType];
return Channel[method](params);
}
}
}
Channel.do('channel-create', 'MyChannel');
Channel.do('channel-user-count', 1000);
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编辑:即使上述方法可行,正如@Ryan在他的回答中提到的那样,直接在map中提供功能更为简洁。
private static methodMap: MethodMap = {
'channel-create': Channel.create,
'channel-user-count': Channel.userCount,
'channel-close': Channel.close,
};
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