Pgsql错误:您可能需要添加显式类型转换

Chr*_*ian 15 postgresql heroku

我的网站工作正常,直到我将它部署到heroku,问题是heroku使用pgsql,我正在使用mysql和laravel框架.

我的疑问是

$patient = Patient::where('patient_address', 'ILIKE' ,'%' . $request->input)->where('patient_sex', 'ILIKE' ,'%' . $request->gender)->whereHas('users', function($q) use($vaccine_id){
        $q->where('vaccine_id','ILIKE','%' . $vaccine_id);
    })->get();
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这是我将它部署到heroku时所得到的

SQLSTATE[42883]: Undefined function: 7 ERROR: operator does not exist: integer ~~* unknown LINE 1: ...ient_id" = "patients"."PatientID" and "vaccine_id" ILIKE $3)

HINT: No operator matches the given name and argument type(s). You might need to add explicit type casts. (SQL: select * from "patients" where "patient_address" ILIKE %San Francisco and "patient_sex" ILIKE % and exists (select * from "vaccines" inner join "immunizations" on "vaccines"."VaccineID" = "immunizations"."vaccine_id" where "immunizations"."patient_id" = "patients"."PatientID" and "vaccine_id" ILIKE %))

我已经尝试使用像CAST(vaccine_id AS VARCHAR)这样的强制转换,我没有得到错误,但它没有返回任何结果.

Rom*_*huk 17

问题出在这里:

$q->where('vaccine_id','ILIKE','%' . $vaccine_id)
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看起来像vaccine_id是整数,你不能使用运算符ILIKE来整数.试试'='

如果要使用LIKE,ILIKE或其他文本运算符,则必须将数据转换为文本.在SQL中它必须看起来像:

WHERE "vaccine_id"::text ILIKE val
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代替

WHERE "vaccine_id" ILIKE val
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小智 6

你可以这样做:

$q->where('cast(vaccine_id AS VARCHAR)','LIKE','%' . $vaccine_id)
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或者

$q->where('cast(vaccine_id AS TEXT)','LIKE','%' . $vaccine_id)
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