正则表达式：匹配连续的标点符号并替换为第一个

Question

I am trying to remove some predefined consecutive punctuation marks and replace them with the first. Thus:

1. u.s., -> u.s.
2. u.s. -> u.s.
3. u.s.! -> u.s.
4. hiiii!!!, -> hiiii!

I tried the following code:

import re
r = re.compile(r'([.,/#!$%^&*;:{}=-_`~()])*\1')
n = r.sub(r'\1', "ews by almalki : Tornado, flood deaths reach 18 in U.s., more storms ahead ")
print(n)

Answer 1

您只需要捕获第一个标点符号并匹配其余的：

([.,/#!$%^&*;:{}=_`~()-])[.,/#!$%^&*;:{}=_`~()-]+

见正则表达式演示

请注意，-必须将放在字符类的末尾（或开始），以免创建范围（否则可以在字符类内部转义）。

详细资料：

• ([.,/#!$%^&*;:{}=_`~()-]) -使用您定义的标点符号捕获组
• [.,/#!$%^&*;:{}=_`~()-]+ -1+个标点符号

Python演示：

import re
r = re.compile(r'([.,/#!$%^&*;:{}=_`~()-])[.,/#!$%^&*;:{}=_`~()-]+')
n = r.sub(r'\1', "ews by almalki : Tornado, flood deaths reach 18 in U.s., more storms ahead ")
print(n)