Yog*_*Rai 4 spring-mvc swagger swagger-ui spring-boot swagger-2.0
我正在使用Swagger 2进行API UI.所以,我gradle.build有:
compile "io.springfox:springfox-swagger2:${swaggerVersion}"
compile "io.springfox:springfox-swagger-ui:${swaggerVersion}"
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我已将Swagger配置如下:
@Configuration
@Profile("!production")
@EnableSwagger2
@ComponentScan(basePackageClasses = com.company.controllers.ContentController.class)
public class SwaggerConfiguration {
@Autowired
private BuildInfo buildInfo;
@Bean
public Docket awesomeApi() {
return new Docket(DocumentationType.SWAGGER_2)
.apiInfo(this.awesomeApiInfo())
.select()
.apis(Predicates.not(RequestHandlerSelectors.basePackage("org.springframework.boot")))
.build();
}
private ApiInfo awesomeApiInfo() {
return new ApiInfoBuilder()
.title("Awesome API - build #" + this.buildInfo.getVersion())
.description("Enter the IDs in order to look for the content")
.version("0.1")
.build();
}
}
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我正在获取我已经定义的api端点,但也获得了如下的Spring MVC端点:
现在,我需要摆脱这些mvc端点.
任何帮助都非常感谢!!
Yog*_*Rai 10
哦......实际上这是我的愚蠢错误.我更改了RequestHandlerSelectors以从我自己的控制器包中仅选择端点,如下所示:
@Bean
public Docket awesomeApi() {
return new Docket(DocumentationType.SWAGGER_2)
.apiInfo(this.awesomeApiInfo())
.select()
.paths(PathSelectors.any())
.apis(RequestHandlerSelectors.basePackage("com.company.awesome.controllers"))
.build();
}
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这只显示了controller包中类中映射的端点.
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