nil*_*far 9 python import sqlalchemy blueprint flask
我是bluprint的新手,并且将db导入mydatabase.py文件是一个模型文件.
我遇到过这个错误:
ImportError:无法导入名称'db'
我项目的树
nikoofar/
run.py
bookshelf/
__init__.py
mydatabase.py
main/
controllers.py
__init__.py
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run.py
from bookshelf import app
if __name__ == '__main__':
app.run(debug=True, port=8000)
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bookshelf/intit .py
from flask import Flask
from bookshelf.main.controllers import main
from flask_sqlalchemy import SQLAlchemy
from mydatabase import pmenu
app = Flask(__name__, instance_relative_config=True)
db = SQLAlchemy(app)
db.init_app(app)
application.config['SQLALCHEMY_DATABASE_URI'] = 'mysql+pymysql://username:password@localhost/databasename'
app.config.from_object('config')
app.register_blueprint(main, url_prefix='/')
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bookshelf/main/controllers.py
from flask import Blueprint
from bookshelf.mydatabase import *
from flask_sqlalchemy import SQLAlchemy
main = Blueprint('main', __name__)
@main.route('/')
def index():
g = pmenu.query.all()
print (g)
return "ok"
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问题回到了from bookshelf import db,如果我删除它,错误将更改为:
ImportError:无法导入名称'db'
bookshelf/mydatabase.py
from bookshelf import db
class pmenu(db.Model):
__tablename__ = 'p_menu'
id = db.Column(db.Integer, primary_key=True)
txt = db.Column(db.String(80), unique=True)
link = db.Column(db.String(1024))
def __init__(self, txt, link):
self.txt = txt
self.link = link
def __repr__(self):
return "{'txt': " + self.txt + ", 'link':" + self.link + "}"
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有解决方案吗
Cod*_*ker 34
这实际上是一个简单但令人沮丧的问题.问题是你是从国外进口主要BEFORE要创建的实例db在__init__.py
如果将导入移到您之后db = SQLAlchemy(app),它将起作用:
from flask import Flask
from flask_sqlalchemy import SQLAlchemy
app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = 'mysql+pymysql://uername:password@localhost/test'
db = SQLAlchemy(app)
from bookshelf.main.controllers import main #<--move this here
app.register_blueprint(main, url_prefix='/')
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