React - 子组件可以将值发送回父表单

Kay*_*ote 16 javascript forms components input reactjs

InputField&Button是进入一个表单创建一个表单自定义组件.我的问题是如何将数据重新发送到表单,以便在按钮单击时,我可以使用数据(用户名和密码)在表单上激活ajax:

export default auth.authApi(
  class SignUpViaEmail extends Component{

    constructor(props){
      super(props);
      this.state = {
        email : "",
        password : ""
      };
      this.storeEmail = this.storeEmail.bind( this );
      this.storePassword = this.storePassword.bind( this );
    }

    storeEmail(e){
      this.setState({ email : e.target.value });
    }

    storePassword(e){
      this.setState({ password : e.target.value });
    }

    handleSignUp(){
      this.props.handleSignUp(this.state);
    }

    render(){
      return(
        <div className="pageContainer">

          <form action="" method="post">
            <InputField labelClass = "label"
                        labelText = "Username"
                        inputId = "signUp_username"
                        inputType = "email"
                        inputPlaceholder = "registered email"
                        inputClass = "input" />
            <Button btnClass = "btnClass"
                    btnLabel = "Submit"
                    onClickEvent = { handleSignUp } />
          </form>
        </div>
      );
    }

  }
);
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或者不建议我不应该在表单中创建自定义子组件?

子组件=> InputField

import React,
       { Component } from "react";

export class InputField extends Component{

  constructor( props ){
    super( props );
    this.state = {
      value : ""
    };
    this.onUserInput = this.onUserInput.bind( this );
  }

  onUserInput( e ){
    this.setState({ value : e.target.value });
    this.props.storeInParentState({[ this.props.inputType ] : e.target.value });
  }

  render(){
    return  <div className = "">
              <label htmlFor = {this.props.inputId}
                     className = {this.props.labelClass}>
                {this.props.labelText}
              </label>
              <input id = {this.props.inputId}
                     type = {this.props.inputType}
                     onChange = {this.onUserInput} />
              <span className = {this.props.validationClass}>
                { this.props.validationNotice }
              </span>
            </div>;
  }
}
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错误:我e.target is undefined在父storeEmail func上收到错误.

小智 43

React的单向数据绑定模型意味着子组件无法将值发送回父组件,除非明确允许这样做.React的做法是将回调传递给子组件(参见Facebook的"表单"指南).

class Parent extends Component {
  constructor() {
    this.state = {
      value: ''
    };
  }

  //...

  handleChangeValue = e => this.setState({value: e.target.value});

  //...

  render() {
    return (
      <Child
        value={this.state.value}
        onChangeValue={this.handleChangeValue}
      />
    );
  }
}

class Child extends Component {
  //...

  render() {
    return (
      <input
        type="text"
        value={this.props.value}
        onChange={this.props.onChangeValue}
      />
    );
  }
}
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请注意,父组件处理状态,而子组件仅处理显示.Facebook的"提升状态"指南是学习如何做到这一点的好资源.

这样,所有数据都存在于父组件(处于状态)中,并且子组件仅被赋予更新该数据的方式(作为props传递的回调).现在您的问题得到了解决:您的父组件可以访问它所需的所有数据(因为数据存储在状态中),但您的子组件负责将数据绑定到它们各自的元素,例如<input>标记.


Ali*_*mad 11

父.js

import React, { Component } from 'react';
import Child from './child'
class Parent extends Component {
  state = {
    value: ''
  }
  onChangeValueHandler = (val) => {
    this.setState({ value: val.target.value })
  }
  render() {
    const { value } = this.state;
    return (
      <div>
        <p> the value is : {value} </p>
        <Child value={value} onChangeValue={this.onChangeValueHandler} />
      </div>
    );
  }
}

export default Parent;
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儿童.js

  import React, { Component } from 'react';
  class Child extends Component {
  render() {
  const { value , onChangeValue } = this.props;
  return (
    <div>
      <input type="text"  value={value} onChange={onChangeValue}/> 
    </div>
  );
}
}
  export default Child;
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你可以看到一个活生生的例子:https : //codesandbox.io/s/two-way-binding-qq1o1?from-embed