Python中的嵌套Defaultdicts

Question

我在嵌套的defaultdict中更新列表时遇到问题.

这是我的代码:

a = ['20160115',    'shadyside medical building',   1, 'Review']
b = ['20160115',    'shadyside medical building',   1, 'Video']
c = ['20160215',    'shadyside medical building',   1, 'Video']
d = ['20160215',    'medical building',             1, 'Video']
f = [a,b,c,d]

nested_dict = defaultdict(dict)

for date,keyword,pos,feature in f:
    nested_dict[keyword].update({feature : [pos]})
    nested_dict[keyword].update({feature : [pos]})

这是输出:

{'shadyside medical building': 
                             {'Review': [1], 
                             'Video': [1]}, 
'medical building': 
                   {'Video': [1]}}

所需的输出是:

{'shadyside medical building': 
                             {'Review': [1], 
                             'Video': [1,1]}, 
'medical building': 
                   {'Video': [1]}}

请注意,视频的第二项已添加到视频列表中.

Answer 1

你没有嵌套任何defaultdicts,所以这样做:

nested_dict = defaultdict(lambda: defaultdict(list))

和

nested_dict[keyword][feature].append(pos)