ric*_*ver 7 sql node.js sequelize.js
我有一个多对多关系,中间有一个连接表。这些表是 Cookoff、Participant 和 CookoffParticipant。我应该提到我不允许 Sequelize 创建或修改我的表,我只是在映射我现有的关系。我需要帮助了解哪些关系选项告诉 sequelize 调用将连接表与主表相关联的外键。
据我了解,Sequelize 假设 CookoffID 和 ParticipantID 是 CookoffParticipant 上的复合主键。在我的情况下,我要求主键是我调用 CookoffParticipantID 的标识列,并在 CookoffParticipant 表中的 CookoffID、ParticipantID 对上创建唯一索引。
当我尝试通过查询 cookoffParticipant 表来获取烹饪和参与者数据时,Sequelize 使用错误的键来完成连接。一定有一些简单的事情我没有做。下面是我的表结构和带有结果的查询。
烹饪桌
var Cookoff = sequelize.define("Cookoff", {
// Table columns
CookoffID: {
type: DataTypes.INTEGER,
primaryKey: true,
autoIncrement: true
},
Title: {
type: DataTypes.STRING,
allowNull: false
},
EventDate: {
type: DataTypes.DATE,
allowNull: false
}
}, _.extend({},
// Table settings
defaultTableSettings,
{
classMethods: {
associate: function(models) {
Cookoff.belongsToMany(models.Participant, {
through: {
model: models.CookoffParticipant
},
as: "Cookoffs",
foreignKey: "CookoffID",
otherKey: "ParticipantID"
});
}
}
}
));
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参会表
var Participant = sequelize.define("Participant", {
// Table columns
ParticipantID: {
type: DataTypes.INTEGER,
primaryKey: true,
autoIncrement: true
},
Name: {
type: DataTypes.STRING(100),
allowNull: false
}
}, _.extend({},
defaultTableSettings,
{
classMethods: {
associate: function(models) {
Participant.belongsToMany(models.Cookoff, {
through: {
model: models.CookoffParticipant
},
as: "Participants",
foreignKey: "ParticipantID",
otherKey: "CookoffID"
});
}
}
}
));
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烹饪参与者表
var CookoffParticipant = sequelize.define("CookoffParticipant", {
CookoffParticipantID: {
type: DataTypes.INTEGER,
allowNull: false,
primaryKey: true,
autoIncrement: true
},
CookoffID: {
type: DataTypes.INTEGER,
allowNull: false,
references: {
model: cookoff,
key: "CookoffID"
}
},
ParticipantID: {
type: DataTypes.INTEGER,
allowNull: false,
references: {
model: participant,
key: "ParticipantID"
}
}
}, _.extend(
{ },
defaultTableSettings,
{
classMethods: {
associate: function (models) {
CookoffParticipant.hasOne(models.Cookoff, { foreignKey: "CookoffID" });
CookoffParticipant.hasOne(models.Participant, { foreignKey: "ParticipantID" });
}
}
}
));
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我的查询
return cookoffParticpants.findOne({
where: { CookoffID: cookoffID, ParticipantID: participantID },
include: [
{ model: participants },
{ model: cookoffs }
]
});
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生成的 SQL
SELECT
[CookoffParticipant].[CookoffParticipantID],
[CookoffParticipant].[CookoffID],
[CookoffParticipant].[ParticipantID],
[Participant].[ParticipantID] AS [Participant.ParticipantID],
[Participant].[Name] AS [Participant.Name],
[Cookoff].[CookoffID] AS [Cookoff.CookoffID],
[Cookoff].[Title] AS [Cookoff.Title],
[Cookoff].[EventDate] AS [Cookoff.EventDate]
FROM [CookoffParticipant] AS [CookoffParticipant]
LEFT OUTER JOIN [Participant] AS [Participant]
ON [CookoffParticipant].[CookoffParticipantID] = [Participant].[ParticipantID] -- This should be CookoffParticipant.ParticipantID
LEFT OUTER JOIN [Cookoff] AS [Cookoff]
ON [CookoffParticipant].[CookoffParticipantID] = [Cookoff].[CookoffID] -- This should be CookoffParticipant.CookoffID
WHERE [CookoffParticipant].[CookoffID] = 1
AND [CookoffParticipant].[ParticipantID] = 6
ORDER BY [CookoffParticipantID]
OFFSET 0 ROWS FETCH NEXT 1 ROWS ONLY;
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您可以看到 Sequelize 试图在 Participant.ParticipantID 上加入 CookoffParticipant.CookoffParticipantID,它应该是 CookoffParticipant.ParticipantID = Participant.ParticipantID,对于 CookoffID 也是如此。我在这里做错了什么?
预先感谢您的帮助。
这是关于您正在寻找的内容的非常好的讨论。他们总结得非常好,说您应该定义直通表并在直通表中声明belongsTo 引用。您的问题可能是您使用了hasOne而不是belongsTo. 我也认为你的as钥匙是向后的。
Cookoff.hasMany(Book, { through: CookoffParticipant })
Participant.hasMany(User, { through: CookoffParticipant })
CookoffParticipant.belongsTo(Cookoff)
CookoffParticipant.belongsTo(Participant)
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这是我用来测试的代码。
Cookoff.js
module.exports = (sequelize, DataTypes) => {
var Cookoff = sequelize.define("Cookoff", {
CookoffID: {
type: DataTypes.INTEGER,
primaryKey: true,
autoIncrement: true
}
}, _.extend(
{},
{
classMethods: {
associate: function(models) {
Cookoff.belongsToMany(models.Participant, {
through: models.CookoffParticipant,
foreignKey: "CookoffID",
otherKey: "ParticipantID"
});
}
}
}
));
return Cookoff;
};
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参与者.js
module.exports = (sequelize, DataTypes) => {
var Participant = sequelize.define("Participant", {
ParticipantID: {
type: DataTypes.INTEGER,
primaryKey: true,
autoIncrement: true
}
}, _.extend(
{},
{
classMethods: {
associate: function(models) {
Participant.belongsToMany(models.Cookoff, {
through: models.CookoffParticipant,
foreignKey: "ParticipantID",
otherKey: "CookoffID"
});
}
}
}
));
return Participant;
};
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CookoffParticipant.js
module.exports = (sequelize, DataTypes) => {
var CookoffParticipant = sequelize.define("CookoffParticipant", {
CookoffParticipantID: {
type: DataTypes.INTEGER,
allowNull: false,
primaryKey: true,
autoIncrement: true
}
}, _.extend(
{},
{
classMethods: {
associate: function(models) {
CookoffParticipant.belongsTo(models.Cookoff, { foreignKey: "CookoffID" });
CookoffParticipant.belongsTo(models.Participant, { foreignKey: "ParticipantID" });
}
}
}
));
return CookoffParticipant;
};
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测试.js
const db = require('../db');
const Cookoff = db.Cookoff;
const Participant = db.Participant;
const CookoffParticipant = db.CookoffParticipant;
let cookoff,
participant;
Promise.all([
Cookoff.create({}),
Participant.create({})
]).then(([ _cookoff, _participant ]) => {
cookoff = _cookoff;
participant = _participant;
return cookoff.addParticipant(participant);
}).then(() => {
return CookoffParticipant.findOne({
where: { CookoffID: cookoff.CookoffID, ParticipantID: participant.ParticipantID },
include: [ Cookoff, Participant ]
});
}).then(cookoffParticipant => {
console.log(cookoffParticipant.toJSON());
});
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