cod*_*in3 1 java rest web-services jax-rs jersey-2.0
我正在从一个基本的 Java 程序向一个 URL 发出 HTTP GET 请求,它恰好是"http://localhost:9992/users/john.doe@example.com":
public class Tester {
public static void main(String[] args) {
HttpRequester.doesUserExist("john.doe@example.com");
}
}
Run Code Online (Sandbox Code Playgroud)
的实现HTTPRequester是这样的:
import java.io.BufferedReader;
import java.io.DataOutputStream;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
public class HttpRequester {
private static HttpURLConnection connection = null;
public static boolean doesUserExist(final String email) {
final String targetUrl = Constants.URL_USER_SRVC + email;
System.out.println(targetUrl);
try {
URL url = new URL(targetUrl);
connection = (HttpURLConnection) url.openConnection();
System.out.println(connection.getRequestMethod());
connection.setRequestMethod("GET");
connection.setRequestProperty("Content-Type", "application/json");
connection.setUseCaches(false);
connection.setDoOutput(true);
DataOutputStream outputStream = new DataOutputStream(
connection.getOutputStream());
outputStream.writeBytes(email);
outputStream.close();
InputStream inputStream = connection.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));
StringBuffer response = new StringBuffer();
String line;
while((line = reader.readLine()) != null) {
response.append(line);
response.append('\r');
}
reader.close();
System.out.println(response.toString());
} catch (Exception e) {
e.printStackTrace();
}
return false;
}
}
Run Code Online (Sandbox Code Playgroud)
嵌入在 Grizzly 服务器中的 web 服务,这里是 API:
@Path("/users")
@Consumes(MediaType.APPLICATION_JSON)
@Produces(MediaType.APPLICATION_JSON)
public class UserResource {
@GET
public List<User> getUsers() {
return UserService.getUsers();
}
@GET
@Path("/{userEmail}")
public User getUser(@PathParam("userEmail") String userEmail) {
return UserService.getUser(userEmail);
}
}
Run Code Online (Sandbox Code Playgroud)
请注意 webservice 和 java 程序是两个独立的项目。当我执行 main 方法时,我在控制台中得到这个错误输出:
java.io.IOException: Server returned HTTP response code: 405 for URL: http://localhost:9992/users/john.doe@example.com
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1627)
at com.axa.visualizr.auth.utils.HttpRequester.doesUserExist(HttpRequester.java:30)
at com.axa.visualizr.auth.core.Tester.main(Tester.java:8)
Run Code Online (Sandbox Code Playgroud)
我认为奇怪的是,at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1627)即使我导入了java.net.HttpURLConnection;. 我曾尝试打开该行上的声明,但 Eclipse 指出它不是该类中的有效行号。
我不知道为什么它说当我有setRequestMethod("GET"). 也许是因为java程序没有在任何类型的服务器上运行?这Tester.java仅用于测试目的,最终我将转移HTTPRequester到另一个 Web 服务并从 Web 服务 A 调用 Web 服务 B。
小智 5
由于您在 requestbody 中传递了一些东西,java 将其解释为 POST 请求。请从您的代码中删除以下几行并尝试:
DataOutputStream outputStream = new DataOutputStream(
connection.getOutputStream());
outputStream.writeBytes(email);
outputStream.close();
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
1582 次 |
| 最近记录: |