SB2*_*055 5 sql sql-server ssms
我使用以下内容列出了重复项:
select s.MessageId, t.*
from Message s
join (
select ToUserId, FromUserId, count(*) as qty
from Message
group by ToUserId, FromUserId
having count(*) > 1
) t on s.ToUserId = t.ToUserId and s.FromUserId = t.FromUserId
Run Code Online (Sandbox Code Playgroud)
现在,如何删除除一条消息之外的所有消息(我正在尝试删除重复项,以便我可以应用唯一索引FromUserId and ToUserId).
Vam*_*ala 18
使用a cte并指定行号,以便删除除重复对之外的所有行号.
with rownums as
(select m.*,
row_number() over(partition by ToUserId, FromUserId order by ToUserId, FromUserId) as rnum
from Message m)
delete r
from rownums r
where rnum > 1
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2264 次 |
| 最近记录: |